Answer:
The Area of Rectangular Garden is 1044 feet²
Step-by-step explanation:
According to question
The perimeter of the garden = 82 ft
Let the length be L ft
The width be W ft
Now as per question
L = 5 + ( 2× W )
∵ Perimeter of Rectangle = 2 × ( Length + Width )
Or , Perimeter of Rectangle = 2 × ( L+ W )
Or, 82 = 2 × ( L+ W )
Or, 82 = 2 × [ 5 + ( 2 ×W ) + W ) ]
Or, 82 = 2 × ( 5 +3W )
Or, 41 = 5 + 3W
Or, 41 - 5 = 3W
So, 3W= 36
∴ W = 
= 12 feet
I.e Width = 12 feet
And L = 5 + ( 2× W )
Or, Length = 5 + 24 = 29 feet
Now The Area of Rectangle = Length × width
So, The Area of Rectangle = 29 ft × 36 ft
The Area of Rectangle is 1044 feet²
Hence The Area of Rectangular Garden is 1044 feet² Answer
And how would I do that via computer? If this is homework, do it your self, it's not that hard. Draw it and scan it (man computer doesn't have the ability to scan things)
If Sa=2πrh+2π
v=π
then the surface area is π
and volume is
(rh-2h)/2r.
Given Sa=2πrh+2π
=π.
We have to find surface area and volume from the given expression.
Volume is basically amount of substance a container can hold in its capacity.
First we will find the value of v from the expression. Because they are in equal to each other, we can easily find the value of v.
2πrh+2πv=πh
Keeping the term containing v at left side and take all other to right side.
2πv=π-2πrh
v=(πh-2πrh)/2π
v=π/2π-2πrh/2π
v=h/2-h/r
v=h(r-2)/2r
Put the value of v in Sa=2πrh+2π
Sa=2πrh+2π*h(r-2)/2r
=2πrh+2πrh(r-2)/2
=2πrh+πrh(r-2)
=2πrh+πh-2πrh
=πh
Hence surface area is πh and volume is h(r-2)/2.
Learn more about surface area at brainly.com/question/16519513
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