In parallelogram WXYZ, the shorter sides are half the length of the longer sides

Mathematics

2 answers:

Sedaia [141]3 years ago

5 0

IT'S A SQUAREEEE

JK IT'S A RECTANGLE

Gemiola [76]3 years ago

5 0

Answer: Alright I know this is late but, the answer is

B) Four

Step-by-step explanation:

In parallelogram WXYZ, the longer sides are three times the length of the shorter sides.

When is says that the longer side is three times the length of the side (Which is 12) That means what ever the number is has to equal to 12, so 3 multiply by 4 equals 12.

Sooo, The answer is 4, Hope I didn't confuse you lol

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Solve for x: 4|2x − 2| + 10 = 34.

fiasKO [112]

Remark
This will have 2 solutions. I will enclose a graph to show how it is done.
4|2x - 2| + 10 = 34 Subtract 10

Solution
4|2x - 2| = 34 - 10
4|2x - 2| = 24 Divide by 4
|2x - 2| = 24/4
|2x - 2| = 6

Solution 1
2x - 2 = 6 Add 2
2x = 6 + 2
2x = 8 Divide by 2
x = 8/2
x = 4

Solution 2
Make the 6 into - 6 and solve again
|2x - 2| = - 6
2x - 2= -6 Add 2 to both sides.
2x = - 6 + 2
2x = - 4 Divide by 2
x = - 4/2
x = - 2

Answer
There are 2 solutions
(-2,0) and (4,0) See the graph below.

5 0

2 years ago

Read 2 more answers

All the information in the photo.

a_sh-v [17]

Answer:

Two angles are called complementary when their measures add to 90 degrees. ∠1 is 60 degrees ∠2 is 30 degrees so if you add it up, the answer is 90 degrees.

∠4 + ∠3 = answer has to be 90 degrees to call it a complementary angle

30 degrees + 60 degrees = 90 degrees

6 0

3 years ago

Mrs. Hawk assigns her students an average of no more than 5 questions on each assignment. On their first 5 assignments Mrs. Hawk

bixtya [17]

Given that <span>Mrs. Hawk assigns her students an average of no more than 15 questions on each assignment. On their first 5 assignments Mrs. Hawk’s students had 11, 10, 13, 14, and 14 questions.

Let x be the number of questions she can have on the sixth assignment, then the inequality that Mrs. Hawk can use to determine the number of questions she can have on the sixth assignment is given by

$\frac{11+10+13+14+14+x}{6} \leq15 \\ \\ \Rightarrow62+x\leq90 \\ \\ \Rightarrow x\leq28$ </span>