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artcher [175]
2 years ago
8

Do this only on number line ​

Mathematics
2 answers:
sveta [45]2 years ago
7 0

Step-by-step explanation:

please mark me as brainlest

Tatiana [17]2 years ago
4 0

#4

  • -2/8=-1/4
  • 3/6=1/2

Refer to the attachment

#2

Mid point:-

  • -2/5+1/2/2
  • -4+5/10/2
  • 1/10/2
  • 1/20

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Select all of the number that round to 4.3 when rounded to the nearest tenth
faltersainse [42]

Answer:

4.29-4.28-4.27-4.26-4.25

Step-by-step explanation:

6 0
3 years ago
Bob's age is 4 times greater than Susanne's age. Dakota is three years younger than Susanne. The sum of Bob's, Susanne's, and Da
Ratling [72]
<span>Susanne is 16 years old.</span>

b = Bob's age

s = Susanne's age

d = Dakota's age

Bob's age is 4 times greater than Susanne's age:

b = 4s

Dakota is three years younger than Susanne:

d = s - 3

The sum of Bob's, Susanne's, and Dakota's ages is 93:

b + s + d = 93


 solve these equations:

b = 4s

d = s - 3

b + s + d = 93


and get:

b = 64 years

s = 16 years

(remember that s = Susanne)

d = 13 years
6 0
3 years ago
I can't figure out how to do (i + j) x (i x j)for vector calc
Vinil7 [7]

In three dimensions, the cross product of two vectors is defined as shown below

\begin{gathered} \vec{A}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \\ \vec{B}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k} \\ \Rightarrow\vec{A}\times\vec{B}=\det (\begin{bmatrix}{\hat{i}} & {\hat{j}} & {\hat{k}} \\ {a_1} & {a_2} & {a_3} \\ {b_1} & {b_2} & {b_3}\end{bmatrix}) \end{gathered}

Then, solving the determinant

\Rightarrow\vec{A}\times\vec{B}=(a_2b_3-b_2a_3)\hat{i}+(b_1a_3+a_1b_3)\hat{j}+(a_1b_2-b_1a_2)\hat{k}

In our case,

\begin{gathered} (\hat{i}+\hat{j})=1\hat{i}+1\hat{j}+0\hat{k} \\ \text{and} \\ (\hat{i}\times\hat{j})=(1,0,0)\times(0,1,0)=(0)\hat{i}+(0)\hat{j}+(1-0)\hat{k}=\hat{k} \\ \Rightarrow(\hat{i}\times\hat{j})=\hat{k} \end{gathered}

Where we used the formula for AxB to calculate ixj.

Finally,

\begin{gathered} (\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=(1,1,0)\times(0,0,1) \\ =(1\cdot1-0\cdot0)\hat{i}+(0\cdot0-1\cdot1)\hat{j}+(1\cdot0-0\cdot1)\hat{k} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=1\hat{i}-1\hat{j} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=\hat{i}-\hat{j} \end{gathered}

Thus, (i+j)x(ixj)=i-j

8 0
1 year ago
Write an ordered pair for the point
aleksandr82 [10.1K]

Answer:

(0, 1)

Step-by-step explanation:

The point lies on the line x = 0.

The point lies on the line y = 1.

Where both lines intersect, that is the coordinate.

(x, y)

(0, 1)

5 0
4 years ago
Read 2 more answers
PLEASE HELP ME OUT!!!
igor_vitrenko [27]
Well, first, the equation that you are looking for is Y = MX + B. To find B, look at the first dot on the Y-axis. It starts at positive 3, so, you know your equation will end with +3. Next, to find MX, start at the either dot, and find the Rise/Run. In this particular equation, the rise is 1, and, the run is -2, because it's going backwards (negative line). Meaning, the line's equation would be, f( x )= -1/2x + 3.
5 0
3 years ago
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