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2 years ago

Which of the following lists 3/6, 112, 15/18 in order from least to greatest?

Mathematics

2 answers:

Leona [35]2 years ago

4 0

Answer:

3/6 ⇒ 9/12⇒ 15/18

Step-by-step explanation:

To put the following lists 3/6,9/12, 15/18 in order from least to greatest we can turn the fraction into decimal..

3/6 = 0.5

15/18 = 0.83333333333

9/12= 0.75

Hence from least to greatest:

0.5,0.75, 0.83333333333

Also know as:

3/6,9/12,15/18

~lenvy~

Inessa [10]2 years ago

4 0

Answer:

Order 3/6, 9/12, and 15/18 from least to greatest.

Keep in mind, there are multiple ways into finding the answer to this question.

First, we must simplify these fractions as much as possible then find a possible common denominator.

3/6 simplifies to 1/2

9/12 simplifies to 3/4

15/18 simplifies to 5/6

Now we have fractions of 1/2(3/6), 3/4(9/12), and 5/6(15/18).

If we look at these fractions, we can see that they have a common denominator of 12. So let's convert these fractions into having a denominator of 12;

1/2 x 6/6 = 6/12

3/4 x 3/3 = 9/12

5/6 x 2/2 = 10/12.

So now we have the fractions 6/12(3/6), 9/12(9/12), and 10/12(5/6).

These are already ordered from least to greatest.

So therefore, this'll be ordered;

3/6, 9/12, and 15/18.

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Our school has 6 Grade and 786 students. What is the average number of students in each grade

Harrizon [31]

Answer:

The average number of students in each grade is 131 students

Step-by-step explanation:

In order to get this answer, you will divide 786 by 6 because 768 is the number of students in your school and 6 is the number of grades. Once you divided 786 and 6, you should get 131. Hope this helps! :)

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3 0

3 years ago

Read 2 more answers

Consider m = y2 - y1/ x2 - x1 . Which x1 and x2-values would determine that the line is vertical? Justify your answer

Y_Kistochka [10]

Answer:

$x_2=x_1$

Step-by-step explanation:

We were given the slope formula;

$m=\frac{y_2-y_1}{x_2-x_1}$

This line is vertical if the denominator is zero.

That is when $x_2-x-1=0$

This implies that;

$x_2=x_1$

Justification;

When $x_2=x_1$ , then, the line passes through;

$(x_1,y_1)$ and $(x_1,y_2)$

The slope now become

$m=\frac{y_2-y_1}{x_1-x_1}=\frac{y_2-y_1}{0}$

The equation of the line is

$y-y_1=\frac{y_2-y_1}{0}(x-x_1)$

This implies that;

$0(y-y_1)=(y_2-y_1)(x-x_1)$

$0=(y_2-y_1)(x-x_1)$

$\frac{0}{y_2-y_1}=(x-x_1)$

$0=(x-x_1)$

$x=x_1$ ... This is the equation of a vertical line.

3 0

3 years ago

hannahs exercise goal is to walk at least 6 1/2 miles this week. she has already walked 2 3/4 miles this week. write and solve a

Ne4ueva [31]

We want to write an inequality that tells how much Hannah should walk this week. The inequality will be:

x ≥ (3 + 3/4) mi

<h3>Finding the inequality:</h3>

We know that she already did walk 2 3/4 miles this week, and she wants to walk at least 6 1/2 miles.

So to reach that minimum, she needs to walk:

(6 1/2)mi - (2 + 3/4) mi = (3 + 3/4) mi

And she can walk that or more, so the inequality is:

x ≥ (3 + 3/4) mi

Where x represents how much she will walk this week.

If you want to learn more about inequalities, you can read:

brainly.com/question/11234618

6 0

2 years ago

The sum of a rational number and an irrational number

vitfil [10]

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7 0

3 years ago

Find the general indefinite integral. (Use C for the constant of integration. Remember to use absolute values where appropriate.

Maru [420]

Answer:

$9\text{ln}|x|+2\sqrt{x}+x+C$

Step-by-step explanation:

We have been an integral $\int \frac{9+\sqrt{x}+x}{x}dx$ . We are asked to find the general solution for the given indefinite integral.

We can rewrite our given integral as:

$\int \frac{9}{x}+\frac{\sqrt{x}}{x}+\frac{x}{x}dx$

$\int \frac{9}{x}+\frac{1}{\sqrt{x}}+1dx$

Now, we will apply the sum rule of integrals as:

$\int \frac{9}{x}dx+\int \frac{1}{\sqrt{x}}dx+\int 1dx$

$9\int \frac{1}{x}dx+\int x^{-\frac{1}{2}}dx+\int 1dx$

Using common integral $\int \frac{1}{x}dx=\text{ln}|x|$ , we will get:

$9\text{ln}|x|+\int x^{-\frac{1}{2}}dx+\int 1dx$

Now, we will use power rule of integrals as:

$9\text{ln}|x|+\frac{x^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}+\int 1dx$

$9\text{ln}|x|+\frac{x^{\frac{1}{2}}}{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2x^{\frac{1}{2}}+\int 1dx$

$9\text{ln}|x|+2\sqrt{x}+\int 1dx$

We know that integral of a constant is equal to constant times x, so integral of 1 would be x.

$9\text{ln}|x|+2\sqrt{x}+x+C$

Therefore, our required integral would be $9\text{ln}|x|+2\sqrt{x}+x+C$ .

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3 years ago