To answer this, let's first describe the two areas and obtain the pertinent dimensions from them.
The area of the square hole is 5 cm^2. Since A = s^2, where s is the length of a side of the square, s = +√5 in this situation. +√5 is approx. 2.24 cm.
The area of the round peg is 5 cm^2 also, but the area is calculated using a different formula: A = πr^2, where r is the radius of the circle. Solving for r^2, we get:
r^2 = A/π. Here, r^2 = (5 cm^2)/π = 5π, so that:
r = +√(5π). This is approx. 3.96 cm, and so the diameter is twice that, or 7.93 cm.
So there's plenty of room for the round peg to enter the square hole, but not the other way around!
Answer: The value of x is 155/79.
Step-by-step explanation:
13(6x -5 )-x= 13 -2(x +1)
78x - 65- x = 13 -2x -2
77x -65 = 11-2x
79x -65 =11
79x =76
x = 76/79 76/ 79 + 1/1 = 155/79
Answer:
Bottom left.
Step-by-step explanation:
You can try plugging in points as well but that graph is the general shape of x^3, just compressed by 1/3.
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