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Law Incorporation [45]
3 years ago
11

Factor the expression 20x + 12y - 28

Mathematics
2 answers:
steposvetlana [31]3 years ago
5 0
<h3>hello!</h3>

========================================

In order to factor this expression, we should factor out the common term (divide all terms in the polynomial by the common term)

In this case, the common term is

4

Note:- Usually, we factor out the G.C.F. (Greatest Common Factor)

So here, the G.C.F. is 4.

Why 4? Because in this trinomial (a polynomial with 3 terms) all 3 terms are divisible by 4.

So divide all the terms

5x

3y

-7

Put 4 outside the parentheses:

4(5x+3y-7)

Is the trinomial in its simplest form? Sure!

Hence, we are done! :)

================================

<h3>note:-</h3>

Hope everything is clear; if you need any more clarification/explanation, kindly let me know, and I will comment and/or edit my answer. :)

Evgen [1.6K]3 years ago
4 0

Answer:

\boxed{\sf{4(5x+3y-7)}}

Step-by-step explanation:

It is necessary to find the factors and solve them using their expressions in order to solve this problem.

<h3>20x+12y-28</h3>

7*4=28

3*4=12

5*4=20

Rewrite the problem down.

5*4x+3*4y+7*4

Solve.

Common term of 4.

<u>4(5x+3y-7)</u>

  • <u>Therefore, the final answer is 4(5x+3y-7).</u>

<u></u>

I hope this helps you! Let me know if my answer is wrong or not.

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33 percent subtract 16 percent ​
Alexandra [31]

Answer: 0.2772 or 27.72%

<em><u>WORK </u></em><em>↓</em>

0.2772/ 1 × 100/100 = 27.72/100

* Hopefully this helps:) Mark me the brainliest:)!!!!

7 0
4 years ago
In a class 26 of students, 17 have a brother and 7 have a sister. There are 4 students who do not have any siblings. What is the
Anni [7]
Number of students = 26
Number of students without siblings = 4 
⇒ Number of students with at least one siblings = 26 - 4 = 22
 
Number of students with brothers = 17
Number of students with sisters = 7
⇒ Number of students with both a brother and a sister = 17 + 7 - 22 = 2

P(student has a brother, given that they have a sister) = 2/7

Answer: 2/7
6 0
3 years ago
Plz help me with this
stiks02 [169]

Answer:  FALSE

<u>Step-by-step explanation:</u>

\text{Pythagorean formula is } (x)^2+(y)^2=(hypotenuse)^2\\\text{Pythagorean triple states that each leg and the hypotenuse are integers.}\\\\\text{Given:}\\leg_1=x^2-y^2 \qquad \qquad leg_2=2xy\qquad \qquad hypotenuse=x^2+y^2\\\\\text{Let x = 16 and  y = 2k + 1 (the odd leg).}\\\text{Need to show that the hypotenuse is an integer:}

(16)^2+(2k+1)^2=(hypotenuse)^2\\256+4k^2+4k+1=(hypotenuse)^2\\4k^2+4k+257=(hypotenuse)^2\\4(k^2+k+64.25)=(hypotenuse)^2\\k^2+k+64.25\text{ is not a perfect square because }\sqrt{64.25} \text{ is irrational}\\\text{Therefore, the hypotenuse is not an integer.}\\\\\text{The statement is FALSE.}  

3 0
3 years ago
Plz help me with us
nata0808 [166]

Answer:

11 = m/2 +7

4 = m/2

m = 8

Step-by-step explanation:

5 0
3 years ago
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The<br>perimeter of<br>rectangle is 36 cm<br>If its width is 7cm Exaluate to its length<br>​
maxonik [38]

Answer:

11

Step-by-step explanation:

8 0
3 years ago
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