since T is the midpoint of SU, then ST = TU.
![\bf \stackrel{10x-14}{\boxed{S}\rule[0.35em]{10em}{0.25pt}} T\stackrel{5x+16}{\rule[0.35em]{10em}{0.25pt}\boxed{U}} \\\\\\ \stackrel{ST}{10x-14}=\stackrel{TU}{5x+16}\implies 5x-14=16\implies 5x=30\implies x=\cfrac{30}{5}\implies x=6 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{ST}{10(6)-14\implies 46}~\hfill \stackrel{TU}{TU=ST=46}~\hfill \stackrel{SU}{ST+TU=92}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B10x-14%7D%7B%5Cboxed%7BS%7D%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%7D%20T%5Cstackrel%7B5x%2B16%7D%7B%5Crule%5B0.35em%5D%7B10em%7D%7B0.25pt%7D%5Cboxed%7BU%7D%7D%20%5C%5C%5C%5C%5C%5C%20%5Cstackrel%7BST%7D%7B10x-14%7D%3D%5Cstackrel%7BTU%7D%7B5x%2B16%7D%5Cimplies%205x-14%3D16%5Cimplies%205x%3D30%5Cimplies%20x%3D%5Ccfrac%7B30%7D%7B5%7D%5Cimplies%20x%3D6%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7BST%7D%7B10%286%29-14%5Cimplies%2046%7D~%5Chfill%20%5Cstackrel%7BTU%7D%7BTU%3DST%3D46%7D~%5Chfill%20%5Cstackrel%7BSU%7D%7BST%2BTU%3D92%7D)
Hi, so first u have to multiple 12×6=72 then next u divide by 2 which must five u a food start
The first pipe fills 1/8 of a pool in one hr.
The second pipe fills 1/4 of a pool in one hr.
(1/8+1/4)2= 3/4 done by the first two pipes in 2 hours.
Therefore the last pipe must do 1 1/4 of the filling in 2 hours, which is 5/8 per hour.
5/8x=1
x=8/5
It takes the third pipe 1 hour and 36 minutes to fill it by itself.
Answer:
The correct option to tell whether a relationship is proportional or not is;

Step-by-step explanation:
A proportional relationship is a relationship between two variables, 'x', and 'y' such that they have equivalent ratio, such that all values of variable 'y' are given by the product of the values of the variable 'x' and a constant, 'k'
Therefore, y = k · x, from which we have;

Therefore we can use
to tell whether a relationship is proportional or not proportional.
Left side I think is A is 12 sandcastles and B is 20 sandcastles.