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valentina_108 [34]
2 years ago
13

Write an equation that you can use to solve for x. Enter your answer in the box.

Mathematics
2 answers:
mario62 [17]2 years ago
4 0

Answer:

40 degrees

100-60=40

Step-by-step explanation:

The angle x is in another angle that looks like 100 and 100 minus 60 is 40.

Hope this helps and if it is correct.

Law Incorporation [45]2 years ago
4 0

Answer:

Step-by-step explanation:

Remark

x + 60 together make up an angle that is vertically opposite the 100 degree angle.

Vertically opposite angles are equal.

Equation

x + 60 = 100

Solution and Answer

x + 60 = 100                    Subtract 60 from both sides.

x + 60-60 = 100 - 60      Combine

Answer: x = 40

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Find the Area of the composite shape shown below:
spin [16.1K]

Answer:

104 ft

Step-by-step explanation:

6 x 4 = 24

16 x 8 = 128

128 - 24 = 104 ft

7 0
2 years ago
I need help with #11
Troyanec [42]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template in mind, let's take a peek at this function

\bf \begin{array}{lllcclll}
y=&2(&1x&-2)^2&-4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
A\cdot B=2\impliedby \textit{shrunk by a factor of 2, of half-size}\\\\
\cfrac{C}{B}= \cfrac{-2}{1}\implies -2\impliedby \textit{horizontal right shift of 2 units}\\\\
D=-4\impliedby \textit{vertical down shift of 4 units}

so, the graph of y=2(x-2)²-4, is really the same graph of y=x², BUT, narrower, and moved about horizontally and vertically
8 0
3 years ago
Read 2 more answers
Can you please help me with this, I have no idea
sergejj [24]
I have no clue sorry
6 0
3 years ago
John is having a barbeque and purchased 12.25 pounds of hamburger for $3.12 per pound. How much did John spend on
Wewaii [24]

Answer: 38.22, i hope this helps!!

3 0
2 years ago
Helppppopleaseee????
rosijanka [135]

Answer:

LQ = 5

Median = 6

Step-by-step explanation:

\frac{n+1}{2} gives us 5.5, so we do the average of position 5 and 6. This gives us 6, so the median is 6.

Now we find the median of the bottom half of the numbers, which is 5, so the LQ is 5.

Now we find the median of the upper half of the numbers, which is 7, so the UQ is 7.

7 0
2 years ago
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