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sergeinik [125]
3 years ago
13

Simplify: 3 . 3^2 + 8 ÷ 2 - (4 + 3) A: 32 B: 24 C: 23 D: 30

Mathematics
1 answer:
yaroslaw [1]3 years ago
7 0

Answer:

its none of these answers ;-;

Step-by-step explanation:

3^2 + 8 ÷ 2 - (4 + 3)

we do what's in parentheses first. (pemdas)

so now we have, 3^2 + 8 ÷ 2 - 7

next exponents, 3^2=9

9 + 8 ÷ 2 - 7

next division, 8÷2=4

9 + 4 - 7

next addition, 9+4=13

13-7

finally subtraction, 13-7=6

final answer: 6

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Model with mathematics. A bus can hold no more than 86 students. Write an inequality to describe the situation. - Graph the ineq
ki77a [65]

Answer:

x less than or equal to 86

Step-by-step explanation:

this is because x represents the number of people since the bus cant hold anymore than 86 you can only have 86 or less people on the bus

8 0
2 years ago
A department store sold 51 51 shirts one day. All short-sleeved shirts cost $14.00 $ 14.00 each and all long-sleeved shirts cost
Dmitrij [34]

Answer:

28 short-sleeved shirts were sold and 23 long-sleeved shirts were sold.

Step-by-step explanation:

We can solve this question by a system of equations.

I am going to say that:

x is the number of short-sleeved shirts sold.

y is the number of long-sleeved shirts sold.

A department store sold 51 shirts one day.

This means that x + y = 51

All short-sleeved shirts cost $14.00 each and all long-sleeved shirts cost $23.00 each. Total receipts for the day were $921.00.

This means that

14x + 23y = 921

How many of each kind of shirt were sold?

We have to solve the system of equations.

x + y = 51

x = 51 - y

--------------

14x + 23y = 921

14(51 - y) + 23y = 921

714 - 14y + 23y = 921

9y = 207

y = \frac{207}{9}

y = 23

--------

x = 51 - y = 51 - 23 = 28

28 short-sleeved shirts were sold and 23 long-sleeved shirts were sold.

7 0
3 years ago
i have to write equations in standard form using integer coefficients for A,B, and, C Example: y= -8/15x + 1/20
uysha [10]

Answer:

c

Step-by-step explanation:

5 0
3 years ago
Suppose p" must approximate p with relative error at most 10-3 . Find the largest interval in which p* must lie for each value o
goblinko [34]

Answer:

[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]

Step-by-step explanation

The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is

r = |p*-p|/|p|

we want r to be at most 10⁻³, thus

|p*-p|/|p| ≤ 10⁻³

|p*-p| ≤ |p|* 10⁻³

therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval  [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]

8 0
3 years ago
Use x = 3 to identify the value of each expression.<br><br> Exponent Value of expression
natta225 [31]
Dddd$$c &fguhvhjhhujgih’h
5 0
3 years ago
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