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Jlenok [28]
3 years ago
9

What’s the answer ??

Mathematics
1 answer:
ollegr [7]3 years ago
5 0

Answer:

Step-by-step explanation:

radius r = 10/2 = 5 ft

height h = 5 ft

Volume = πr²h = π(5²)(5) = 125π ≈ 392.7 ft³

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Find the measure Of PR
Misha Larkins [42]

Answer:

18

Step-by-step explanation:

The formula for this is a x b = c x d where a is SR, b is FR, c is QR and d is PR. This will give us the equation 9(16) = 8(5x + 8); 144 = 40x + 64; 80 = 40x; x = 2. Now, plug this into PR which will be 5(2)+8 = 18. This is your answer.

3 0
3 years ago
Help with this!!plz. Asap
gizmo_the_mogwai [7]
Hey there! :D

So, we know that there are 3 z's and 3 6's. 

3*z= 3z

6*3= 18 

3(z+6) <== equivalent expression 

3z+18 <== equivalent expression

z is by itself. It shouldn't combine. It should stay the same. 6 as a unit is separate from z. 

Choices "B" and "E" are correct.

I hope this helps!
~kaikers
5 0
3 years ago
What is the product?(x − 3)(2x2 − 5x + 1)
slavikrds [6]
2x^3-11x^2+16x-3

the answew is above^^^^^^^^^^^^^
3 0
3 years ago
Read 2 more answers
Last year, 800 students attended the career fair at west high school. this year,the number of students who attended the career f
Delvig [45]

Answer:

840

Step-by-step explanation:

Last year, 800 students attended the career fair at West High School.  

And, this year the number of students who attended the career fair increased by 5%.

We are asked how many students attended the career fair at West High School this year.

Therefore, the number of students attended the career fair at West High School will be 800[1+\frac{5}{100} ]  =800 \times 1.05 = 840. (Answer)

3 0
3 years ago
The radius of the tires of a car is 18 inches, and they are revolving at the rate of 651 revolutions per minute. How fast is the
Mumz [18]
So the car is moving at 651 revolutions per minute, with wheels of a radius of 18inches

so, one revolution, is just one go-around a circle, and thus 2π, 651 revolutions is just 2π * 651, or 1302π, the wheels are moving at that "angular velocity"

now, what's the linear velocity, namely, the arc covered per minute

well   \bf v=rw\qquad &#10;\begin{cases}&#10;v=\textit{linear velocity}\\&#10;r=radius\\&#10;w=\textit{angular velocity}\\&#10;----------\\&#10;r=18in\\&#10;w=1302\frac{\pi }{min}&#10;\end{cases}\implies v=18in\cdot \cfrac{1302\pi }{min}&#10;\\\\\\&#10;v=\cfrac{23436\pi\ in}{min}

now, how much is that in miles/hrs?  well
let's keep in mind that, there are 12inches in 1foot, and 5280ft in 1mile, whilst 60mins in 1hr

thus   \bf \cfrac{23436\pi\ in}{min}\cdot \cfrac{ft}{12in}\cdot \cfrac{mi}{5280ft}\cdot \cfrac{60min}{hr}\implies \cfrac{23436\cdot \pi \cdot 60\ mi}{12\cdot 5280\ hr}

notice, after all the units cancellations, you're only left with mi/hrs
4 0
3 years ago
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