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2 years ago

12

A lifeguard fills a pool with water at a constant rate. After 1/2 hour, 1/3 of the pool is filled.

2 answers:

dlinn [17]2 years ago

8 0

Answer:

2/3 of an hour

Step-by-step explanation:

Romashka-Z-Leto [24]2 years ago

4 0

Answer: 2/3 of an hour.

Step-by-step explanation: The constant rate of the lifeguard filling the pool is 1/3 of the pool every 1/2 hour. If she fills it for an hour, she'll get 2/3 of the pool filled. Therefore, it'll take the lifeguard 1 hour to fill the pool 2/3 of the way.

Hope this helps! :)

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eimsori [14]

Answer:

cos P = 71.09

Step-by-step explanation:

cos = $\frac{adajcent}{hypotenuse}$

cos P = $\frac{24}{74}$

cos P = 0.324

cos-1 of 0.324 is 71.09

cos P = 71.09

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2 years ago

What is the slope of (-1,6) and (2,3)?

LenKa [72]

Answer:

-1

Step-by-step explanation:

For a line joining two points (x1, y1) and (x2, y2), it's slope is given as:

$\boxed{ \mathsf{slope = \frac{ y_{2} -y _{1}}{ x_{2} - x _{1}} }}$

Here, the two points are (-1, 6) and (2, 3) in place of (x1, y1) and (x2, y2).

Solving for slope:

$\implies \mathsf{ \frac{3 - 6}{2 - ( -1 )} }$

$\implies \mathsf{ \frac{ - 3}{2 + 1 } }$

$\implies \mathsf{ \frac{ - 3}{3 } }$

$\implies \mathsf{ - 1 }$

Hence, the slope of the line joining the given points is <u>-1.</u>

4 0

3 years ago

Find the inverse Laplace transform f(t) of the function F(s). Write uc for the Heaviside function that turns on at c, not uc(t).

zzz [600]

Answer:

F(t) $=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}$

Step-by-step explanation:

We have given $F(S)=\frac{7e^{-7s}}{s^2-49}$

Now $F(S)=e^{-7s}G(s)$

Here $G(S)=\frac{7}{S^2-49}$

Now first find the Laplace inverse of G(S)

Using partial fraction

$\frac{7}{(s+7)(s-7)}=\frac{A}{(S+7)}+\frac{B}{S-7}$

$7=A(S-7)+B(S+7)$

On comparing the coefficient

$A=\frac{1}{2}$ and $B=\frac{-1}{2}$

On putting the value of A and B

$G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}$

Taking inverse Laplace

$G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}$

Now in G(s) there is onether term $e^{-7s}$

So F(t) $=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}$

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