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ira [324]
2 years ago
14

Determine the relationship between the two triangles and whether or not they can be proven to be congruent. ​

Mathematics
1 answer:
Jlenok [28]2 years ago
6 0

Answer:

only five points uneceptableeeeee

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What is the definition of proof in geometry
oksian1 [2.3K]
I'm guessing just to show that you did your work to get the answer.
4 0
3 years ago
Read 2 more answers
The histogram represents the number of gallons of gasoline that drivers purchase weekly. Which bar represents the number of gall
padilas [110]

Answer:

option B) Bar 2

Step-by-step explanation:

The histogram represent the number of gallons of gasoline on x axis.

The number of drivers purchase weekly on y axis.

In this histogram 5 Bars are shown.

First bar represents = 5 drivers

Second bar represents = 6 drivers

Third bar represents = 1 driver

Fourth bar represents = 3 drivers

Fifth bar represents = = 4 drivers

So the second bar represents the the number of gallons most drivers purchased during the week.

Therefore, option B) Bar 2 is the correct answer.

7 0
3 years ago
I’ll mark branliest!
tatuchka [14]

Answer:

D

Step-by-step explanation:

4 0
2 years ago
Maria's math test had 25 questions she got 84% correct how many did she get wrong
inysia [295]
\frac{x}{25}=84% \\  \frac{x}{25}=.84 \\ 25( \frac{x}{25})=(.84)(25) \\ x=21
Maria got 21 correct.

Number wrong = Total - Number right
y = 25 - 21
y = 4

Maria got 4 wrong.

Hope this helps!

7 0
3 years ago
Read 2 more answers
Question :-
DochEvi [55]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  +  \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}

\qquad \sf  \dashrightarrow \:  \bigg( \dfrac{1}{ \sqrt{7 +  \sqrt{5} } } \bigg ) {}^{2}  +  \bigg( \sqrt{7 +  \sqrt{5} } \bigg) {}^{2}  + 2 \cdot \dfrac{1}{ \sqrt{7 +  \sqrt{5} } }  \cdot \sqrt{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{1}{7 +  \sqrt{5} }  + 7 +  \sqrt{5}  + 2

\qquad \sf  \dashrightarrow \: \dfrac{49 + 7 \sqrt{5} + 7 \sqrt{5} + 5 + 14 + 2 \sqrt{5}   }{7 +  \sqrt{5} }

\qquad \sf  \dashrightarrow \: \dfrac{68+ 16 \sqrt{5}    }{7 +  \sqrt{5} }

5 0
2 years ago
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