1-5q+ 2(2.5q+8)
1-5q+5q+16
0+15
15
(The q goes away because in addition a negative and a positive of the same # equal 0 since its 0 there is no letter)
The area of figure ABCDEF can be computed as the sum of the areas of trapezoid ACDF and triangle ABC, less the area of trangle DEF.
trapezoid ACDF area = (1/2)(AC +DF)·(CD) = (1/2)(8+5)(6) = 39
triangle ABC area = (1/2)(AC)(2) = 8
triangle DEF area = (1/2)(DF)(2) = 5
Area of ABCDEF = (ACDF area) + (ABC area) - (DEF area) = 39 +8 -5 = 42
The actual area of ABCDEF is 42 square units.
Answer:
b
Step-by-step explanation:
jus go on the other side of the graph.
Answer:
can i get your snap?
Step-by-step explanation: