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AVprozaik [17]
4 years ago
15

How much is 2/3 a cup plus 2/3 a cup?

Mathematics
2 answers:
zysi [14]4 years ago
7 0
There would be 1 1/3 cups
IgorLugansk [536]4 years ago
7 0
The answer is 1 1/3 as a mixed number , the actual fraction is 4/3.
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Solve for x: 2(10-2x) = 4(3x + 1). Write your answer as a fraction.
qwelly [4]

Answer:

\boxed{x=1}

Step-by-step explanation:

2(10-2x) = 4(3x + 1)

\sf Expand \ brackets.

20 - 4x = 12x + 4

\sf Subtract \ 12x \ and \ 20 \ from \ both \ sides.

20 - 4x - 12x - 20 = 12x + 4 - 12x - 20

-16x = -16

\sf Divide \ both \ sides \ by \ -16.

\displaystyle \frac{-16x}{-16} =\frac{-16}{-16}

x=1

4 0
3 years ago
Read 2 more answers
I Really need help with this!
Scrat [10]
Where the heck did x come from!
5 0
3 years ago
Read 2 more answers
Find the equation of the quadratic function with vertex (– 2, – 6) that goes through the point (-4, -18)
torisob [31]

Answer:

y = -3(x+2)^2 - 6

Step-by-step explanation:

y = a(x+2)^2 -6

-18 = a(-2)^2 - 6

-12 = 4a

a = -3

y = -3(x+2)^2 - 6

3 0
2 years ago
In ΔIJK, k = 57 inches, i = 37 inches and ∠J=141°. Find ∠I, to the nearest degree.
Sonbull [250]

Answer:

<I= 15degrees

Step-by-step explanation:

Using the cosine rule formulae;

j² = i²+k²-2i cos <J

j² = 37²+57² - 2(37)(57)cos <141

j² = 1369+ 3249- 4218cos <141

j² = 4618- 4218cos <141

j² = 4618-(-3,278)

j²= 7,896

j = √7,896

j = 88.86inches

Next is to get <I

i² = j²+k²-2jk cos <I

37² = 88.86²+57² - 2(88.86)(57)cos <I

1369 = 7,896.0996+ 3249- 10,130.04cos <I

1369 = 11,145.0996 - 10,130.04cos <I

1369 - 11,145.0996 = - 10,130.04cos <I

-9,776.0996=- 10,130.04cos <I

cos <I =9,776.0996 /10,130.04

cos<I = 0.96506

<I = 15.19

<I= 15degrees

8 0
3 years ago
A waiter earns $128 for 6 hours
alekssr [168]

Answer:

$21.33

Step-by-step explanation:

If the waiter earns $128 for 6 hours, divide 128 by 6.

21.33...

8 0
3 years ago
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