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3 years ago

14

How many tulips does the store sells? The garden store sells each daisy for 4 dollars and each tulips for 6. How much more money

does the store make fromtje sale of tulips than from the sale of daises?

1 answer:

Montano1993 [528]3 years ago

5 0

24 tulips in total all u had to do was multiple. 4×6= 24

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The area of the rectangle is 6 square feet. If its width is 2 1/7<br> feet, find its length.

densk [106]

Answer:

L = 2 4/5 feet

Step-by-step explanation:

A = L x W

6 = L x 2 1/7

divide both sides by 2 1/7

6 divided by 2 1/7 = L (is the same as multiplying by the reciprocal)

6 x 7/15 = L

L = 14/5 or 2 4/5

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3 years ago

Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation option

denis-greek [22]

Answer:

The probability that he teleports at least once a day = $\mathbf{\frac{5}{9}}$

Step-by-step explanation:

Given -

Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation options teleport ride a dragon or walk to work and in the evening he has the same three choices for his trip home.

Total no of outcomes = 3

P( He not choose teleport in the morning ) = $\frac{2}{3}$

P( He not choose teleport in the evening ) = $\frac{2}{3}$

P ( he choose teleports at least once a day ) = 1 - P ( he not choose teleports in a day )

= 1 - P( He not choose teleport in the morning ) $\times$ P( He not choose teleport in the evening )

= $1 - \frac{2}{3}\times\frac{2}{3}$

= $\frac{5}{9}$

3 0

3 years ago

Germany has a population

egoroff_w [7]

Answer:

C. -186,205

Step-by-step explanation:

636,854 - 827,155 + 684,862 - 680,766

=> 1,321,716 - 1,507,921

=> -186,205

8 0

3 years ago

Find all the zeros if the function including multiplicity f(x)=(x+7)(x-3)^2(x-2+i)(x-2-i)

NISA [10]

Solve for x. The multiplicity of a root is the number of times the root appears.
x=-7 (multiplicity of 1)
x=3 (multiplicity of 2)
x=2-i (multiplicity of 1)
x=2+1 (multiplicity of 1)

6 0

3 years ago

Let X1, X2, ... , Xn be a random sample from N(μ, σ2), where the mean θ = μ is such that −[infinity] < θ < [infinity] and

Sliva [168]

Answer:

$l'(\theta) = \frac{1}{\sigma^2} \sum_{i=1}^n (X_i -\theta)$

And then the maximum occurs when $l'(\theta) = 0$ , and that is only satisfied if and only if:

$\hat \theta = \bar X$

Step-by-step explanation:

For this case we have a random sample $X_1 ,X_2,...,X_n$ where $X_i \sim N(\mu=\theta, \sigma)$ where $\sigma$ is fixed. And we want to show that the maximum likehood estimator for $\theta = \bar X$ .

The first step is obtain the probability distribution function for the random variable X. For this case each $X_i , i=1,...n$ have the following density function:

$f(x_i | \theta,\sigma^2) = \frac{1}{\sqrt{2\pi}\sigma} exp^{-\frac{(x-\theta)^2}{2\sigma^2}} , -\infty \leq x \leq \infty$

The likehood function is given by:

$L(\theta) = \prod_{i=1}^n f(x_i)$

Assuming independence between the random sample, and replacing the density function we have this:

$L(\theta) = (\frac{1}{\sqrt{2\pi \sigma^2}})^n exp (-\frac{1}{2\sigma^2} \sum_{i=1}^n (X_i-\theta)^2)$

Taking the natural log on btoh sides we got:

$l(\theta) = -\frac{n}{2} ln(\sqrt{2\pi\sigma^2}) - \frac{1}{2\sigma^2} \sum_{i=1}^n (X_i -\theta)^2$

Now if we take the derivate respect $\theta$ we will see this:

$l'(\theta) = \frac{1}{\sigma^2} \sum_{i=1}^n (X_i -\theta)$

And then the maximum occurs when $l'(\theta) = 0$ , and that is only satisfied if and only if:

$\hat \theta = \bar X$

6 0

3 years ago