1 answer:
Triangle ABC is similar to triangle DEC, ∠B ≅ ∠E and 3DE = 2BC
<h3>What is transformation?</h3>Transformation is the movement of a point from its initial location to a new location. Types of transformation are <em>rotation, reflection, translation and dilation.</em>
Dilation is the increase or decrease in the size of a figure by a scale factor.
Right triangle ABC is reflected over AC, then dilated by a scale factor of 2/3 to form triangle DEC, hence:
Triangle ABC is similar to triangle DEC, corresponding angles are congruent (∠B ≅ ∠E) and DE = (2/3)BC i.e. 3DE = 2BC
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Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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