Answer:
Step-by-step explanation:
![\frac{1}{2}b^{2} - 6](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Db%5E%7B2%7D%20-%206)
![\frac{1}{2}(4)^{2} - 6](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%284%29%5E%7B2%7D%20-%206)
![\frac{1}{2} * 16 - 6](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2A%2016%20-%206)
![8 - 6](https://tex.z-dn.net/?f=8%20-%206)
![2](https://tex.z-dn.net/?f=2)
Answer:
x ≥ -5
Step-by-step explanation:
If we have a translation to left c units, we write " x + c " in the function, and
If we have a translation to right c units, we write " x - c" in the function
If we have vertical translation up b units, we "add b to the function", and
If we have vertical translation down b units, we "subtract b to the function"
The parent function is ![f(x)=\sqrt{x}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%7Bx%7D)
Since translation left 5 units and up 3 units, we can write:
![f(x)=\sqrt{x+5} + 3](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%7Bx%2B5%7D%20%2B%203)
The domain is affected by the square root sign and we know the number under the square root CANNOT be negative, so we can say:
x + 5 ≥ 0
x ≥ -5
This is the domain.
Answer:
5
Step-by-step explanation:
So we want to find the value of x where the area to the left of it is equal to 0.6.
Let's start by finding the area of the first triangle, between x=0 and x=4.
A = 1/2 bh
A = 1/2 (4) (0.2)
A = 0.4
So we know a > 4. What if we add the area of that rectangle?
A = 0.4 + bh
A = 0.4 + (1) (0.2)
A = 0.6
Aha! So a = 5.
What you do is cross multiply
1.5 x p & 6 x 10
after divide 1.5 on each side to get p alone
1.5p/1.5 & ___/1.5
you should get your answer to what p equals
hope this helped
Step-by-step explanation:
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