All categories

3 years ago

What type of function is y=7(5/4)^x

Mathematics

1 answer:

erica [24]3 years ago

4 0

Answer:

It is a equation

Step-by-step explanation:

Because it has an equal sign if it does not it will be a expression.

You might be interested in

aivan3 [116]

Answer:

non-linear: C, E, F

Step-by-step explanation:

Choices A, B, D are linear functions, so the rest are non-linear: C, E, F

6 0

3 years ago

Chris and Becky are comparing mortgages. The mortgage is for $183,500. If they choose 30 years at 5%, their monthly payment will

Anestetic [448]

Answer:

Total payback for Loan type 1 = $354,625.20

Total payback for Loan type 2 = $278,618.40

Explanation

Total payback of a loan consists of the summation of the amount of mortgage to be paid and total interest to be paid after the given number of years.

Total payback of a loan can also be calculated by multiplying your monthly payment of the loan by the total number of months given for payment.

a. For Loan type 1

In the question we have been given or monthly payment = $985.07

The formula for Total payback for Loan type 1 = Monthly payment × number of months

Numbers of years for payment of loan = 30 years

1 years = 12 months

Hence,

Number of months = 30 years × 12 months

Number of months = 360 months

Total payback of loan = $985.07 × 360 months

= $354,625.20

b. For Loan type 2

In the question we have been given or monthly payment = $1160.91

The formula for Total payback for Loan type 1 = Monthly payment × number of months

Numbers of years for payment of loan = 30 years

1 years = 12 months

Hence,

Number of months = 20 years × 12 months

Number of months = 240 months

Total payback of loan = $1160.91 × 240 months

= $278,618.4

Step-by-step explanation:

4 0

2 years ago

If 28% of a sum is 100.80 what is the sum

Sveta_85 [38]

$360.00*.28= 100.80

Or do a portion 

28%/100%=100.8/x 

Then cross multiply 

10080=28x 

x=360

4 0

3 years ago

Question 7 of 10 What is the solution to this equation

tatyana61 [14]

Answer:

x = 4

Step-by-step explanation:

x + 4(x+5) = 40 (Given)

x + 4x + 20 = 40 (Distribute the 4 into the x and 5)

5x + 20 = 40 (Add like terms)

5x = 20 (Subtract 20 on both sides)

x = 4 (Divide 5 on both sides)

5 0

3 years ago

let x1,x2, and x3 be linearly independent vectors in R^(n) and let y1=x2+x1; y2=x3+x2; y3=x3+x1. are y1,y2,and y3 linearly indep

Nutka1998 [239]

Answer with Step-by-step explanation:

We are given that

$x_1,x_2$ and $x_3$ are linearly independent.

By definition of linear independent there exits three scalar $a_1,a_2$ and $a_3$ such that

$a_1x_1+a_2x_2+a_3x_3=0$

Where $a_1=a_2=a_3=0$

$y_1=x_2+x_1,y_2=x_3+x_2,y_3=x_3+x_1$

We have to prove that $y_1,y_2$ and $y_3$ are linearly independent.

Let $b_1,b_2$ and $b_3$ such that

$b_1y_1+b_2y_2+b_3y_3=0$

$b_1(x_2+x_1)+b_2(x_3+x_2)+b_3(x_3+x_1)=0$

$b_1x_2+b_1x_1+b_2x_3+b_2x_2+b_3x_3+b_3x_1=0$

$(b_1+b_3)x_1+(b_2+b_1)x_2+(b_2+b_3)x_3=0$

$b_1+b_3=0$

$b_1=-b_3$ ...(1)

$b_1+b_2=0$

$b_1=-b_2$ ..(2)

$b_2+b_3=0$

$b_2=-b_3$ ..(3)

Because $x_1,x_2$ and $x_3$ are linearly independent.

From equation (1) and (3)

$b_1=b_2$ ...(4)

Adding equation (2) and (4)

$2b_1==0$

$b_1=0$

From equation (1) and (2)

$b_3=0,b_2=0,b_3=0$

Hence, $y_1,y_2$ and $y_3$ area linearly independent.

5 0

3 years ago