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I am Lyosha [343]
2 years ago
7

Solve for y. 108° 115° 130° 90°

Mathematics
2 answers:
olga nikolaevna [1]2 years ago
7 0

Answer:

y = 115

Step-by-step explanation:

5 angles should total to 540°.

135+112+88+90+y= 540

425+y=540

y = 115

katovenus [111]2 years ago
6 0

Answer: your answer is B. 115

Step-by-step explanation: I just took the test

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The angles of a triangle are described as follows: angle a is the largest angle; it measure is twice the measure of Angle b. The
nikklg [1K]

Answer:

Angle A = 102°

Angle B = 51°

Angle C = 27°

Step-by-step explanation:

angle A = 2b

angle B = b

angle C = 1/3 b + 10

Angle A + Angle B + Angle C = 180

2b + b + 1/3 b + 10 = 180

3 1/3 b + 10 = 180

10/3 b = 170

b = 51

a = 2b = 102

c = 1/3 b + 10 = 1/3 (51) + 10 = 17 + 10 = 27

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What is quivalent to 5/8?
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Answer:

10/16 is also equivalent

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2 years ago
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Answer the question and answer it down below
Sergio039 [100]

Answer:

4:24 p.m.

Step-by-step explanation:

Figure out how often the buses leave at the same time. This is the same as the least common multiple (LCM) of how often they leave the stadium.

The LCM is found by multiplying the maximum number of each prime factor found in any of the numbers.

The prime factors of a number are found by dividing it by whole numbers until the factors are all prime. Prime numbers only have the factors 1 and itself.

6 = 2 X 3

8 = 2 X 2 X 2

The greatest times 2 repeats is three times.

The greatest times 3 repeats is one time.

2 X 2 X 2 X 3 = 24

The LCM is 24, and the buses have the same leaving times every 24 minutes.

Find 24 minutes after 4:00 p.m. Change the minutes only, which are the numbers right of the colon : .

The buses will next leave together at 4:24 p.m.

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3 years ago
A chef made 30 donuts in 60minutes how long would it take him to make 90donits
Oksanka [162]
<span> 30 donuts in 60 minutes
 90 donuts           ?

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answer
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5. The recursive algorithm given below can be used to compute gcd(a, b) where a and b are non-negative integer, not both zero.
s2008m [1.1K]

Implementating the given algorithm in python 3, the greatest common divisors of <em>(</em><em>124</em><em> </em><em>and</em><em> </em><em>244</em><em>)</em><em> </em>and <em>(</em><em>4424</em><em> </em><em>and</em><em> </em><em>2111</em><em>)</em><em> </em>are 4 and 1 respectively.

The program implementation is given below and the output of the sample run is attached.

def gcd(a, b):

<em>#initialize</em><em> </em><em>a</em><em> </em><em>function</em><em> </em><em>named</em><em> </em><em>gcd</em><em> </em><em>which</em><em> </em><em>takes</em><em> </em><em>in</em><em> </em><em>two</em><em> </em><em>parameters</em><em> </em>

if a>b:

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>greater</em><em> </em><em>than</em><em> </em><em>b</em>

return gcd (b, a)

<em>#if</em><em> </em><em>true</em><em> </em><em>interchange</em><em> </em><em>the</em><em> </em><em>Parameters</em><em> </em><em>and</em><em> </em><em>Recall</em><em> </em><em>the</em><em> </em><em>function</em><em> </em>

elif a == 0:

return b

elif a == 1:

return 1

elif((a%2 == 0)and(b%2==0)):

<em>#even</em><em> </em><em>numbers</em><em> </em><em>leave</em><em> </em><em>no</em><em> </em><em>remainder</em><em> </em><em>when</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>2</em><em>,</em><em> </em><em>checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>and</em><em> </em><em>b</em><em> </em><em>are</em><em> </em><em>even</em><em> </em>

return 2 * gcd(a/2, b/2)

elif((a%2 !=0) and (b%2==0)):

<em>#checks</em><em> </em><em>if</em><em> </em><em>a</em><em> </em><em>is</em><em> </em><em>odd</em><em> </em><em>and</em><em> </em><em>B</em><em> </em><em>is</em><em> </em><em>even</em><em> </em>

return gcd(a, b/2)

else :

return gcd(a, b-a)

<em>#since</em><em> </em><em>it's</em><em> </em><em>a</em><em> </em><em>recursive</em><em> </em><em>function</em><em>,</em><em> </em><em>it</em><em> </em><em>recalls</em><em> </em><em>the function</em><em> </em><em>with </em><em>new</em><em> </em><em>parameters</em><em> </em><em>until</em><em> </em><em>a</em><em> </em><em>certain</em><em> </em><em>condition</em><em> </em><em>is</em><em> </em><em>satisfied</em><em> </em>

print(gcd(124, 244))

print()

<em>#leaves</em><em> </em><em>a</em><em> </em><em>space</em><em> </em><em>after</em><em> </em><em>the</em><em> </em><em>first</em><em> </em><em>output</em><em> </em>

print(gcd(4424, 2111))

Learn more :brainly.com/question/25506437

6 0
2 years ago
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