You'll have to test each of the given numbers in the list to determine whether or not it's a solution of the given inequality.
First number: 76
0.75(76+20)≥
Answer:
Step-by-step explanation:
<span>A quadratic equation of the form ax^2 + bx + c has a general solution of the form
x = - b +- b^2 - 4ac/2a
We shall use the expression under the radical in the formular method. The expression under the radical is called the discriminant.
If the discriminant D = b^2 - 4ac > 0 then the quadratic has two distinct real number solutions since the square root of any positive number is it self a positive number.
If D = b^2 - 4ac = 0 then we get expressions of the form (-b + 0) and (-b - 0). Regardless we end up with -b. This means when D = 0 we have one solution.
If D < 0 the quadratic equation has a conjugate pair of complex roots of the form a + bi</span>
4x ≥ 112
It's very simple.Just replace x by the values from A to F so:
A. x = 21 ⇒ 4·21 ≥ 112 ⇒ 84 ≥ 112 - FALSE
B. x = 33 ⇒ 4·33 ≥ 112 ⇒ 132 ≥ 112 - TRUE
C. x = 27 ⇒ 4·27 ≥ 112 ⇒ 98 ≥ 112 - FALSE
D. x = 1 ⇒ 4·1 ≥ 112 ⇒ 4 ≥ 112 - FALSE
E. x = 28 ⇒ 28·4 ≥ 112 ⇒ 112 ≥ 112 - TRUE
F. x = 25 ⇒ 25·4 ≥ 112 ⇒ 100 ≥ 112 - FALSE
ANSWER : 33,28