Answer:
KPF = 9 and H = 129
Step-by-step explanation:
An inscribed quadrilateral in a circle has all diagonal angles add up to 180, so we can use this to find the angles of the quadrilateral.
H= 180-EPK and K = 180-E so H = 129 and K = 60
Now PF and EH are parallel, so PE is a transversal. That means FPE = 180 - E = 60. Now it's pretty easy to solve for KPF = FPE - EPK = 60 - 51 = 9.
Let me know if you don't see how I did any of this and I'll be happy to explain it..
The slope for this line would be 2
Answer:
uhm wrong guestion
Step-by-step explanation :
sorry
Answer:
Difference of squares:
y^4−25
16x^2−81
Not difference of squares:
20m^2n^2−121
p^8−q^5
Step-by-step explanation:
y^4−25
(y²)² - 5²
16x^2−81
(4x)² - 9²
20m^2n^2−121
20 is not a perfect square
p^8−q^5
q⁵ is not a perfect square
