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Zigmanuir [339]
2 years ago
14

Which of the following best describes the graphs below?

Mathematics
1 answer:
Leya [2.2K]2 years ago
4 0

Answer:

Step-by-step explanation:

D

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Given: PKHE - inscribed, m∠E=120°<br> m∠EPK=51°, PF ∥EH<br> Find: m∠KPF, m∠H.
3241004551 [841]

Answer:

KPF = 9 and H = 129

Step-by-step explanation:

An inscribed quadrilateral in a circle has all diagonal angles add up to 180, so we can use this to find the angles of the quadrilateral.  

H= 180-EPK and K = 180-E so H = 129 and K = 60

Now PF and EH are parallel, so PE is a transversal.   That means FPE = 180 - E = 60.  Now it's pretty easy to solve for KPF = FPE - EPK = 60 - 51 = 9.

Let me know if you don't see how I did any of this and I'll be happy to explain it..

3 0
2 years ago
Given the line: y=2x+3.<br> What is theslope of a line perpendicular to the given line
GuDViN [60]
The slope for this line would be 2
5 0
2 years ago
Please help!!!!!!!!!
Xelga [282]

Answer:

uhm wrong guestion

Step-by-step explanation :

sorry

7 0
3 years ago
C = 7a^4+ + 5a²b2 – 3b^4<br> D=5a^4 + 7a²b^2 + 3b^4<br> C - D =
Gekata [30.6K]

Answer:

2a^4 +12a

2 {a}^{4}  + 12 { a}^{2}  \\  \times  \times

5 0
2 years ago
Read 2 more answers
Help quick please!!
Korolek [52]

Answer:

Difference of squares:

y^4−25

16x^2−81

Not difference of squares:

20m^2n^2−121

p^8−q^5

Step-by-step explanation:

y^4−25

(y²)² - 5²

16x^2−81

(4x)² - 9²

20m^2n^2−121

20 is not a perfect square

p^8−q^5

q⁵ is not a perfect square

3 0
2 years ago
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