Cross multiply and solve
1(y^2-9)=6(y-3)
y^2-9= 6y-18
y^2-6y-9+18=0
y^2-6y+9=0
(y-3)(y-3)=0
(y-3)=0
y=3
When you plug y in however, it makes the denominator 0, making both fractions undefined.
Final answer: No real solution
Answer:
Hello,
Step-by-step explanation:

X²-2x=x
x^2-2x-x=0
x^2-3x=0
x^2=3x
x(x-3)
x=3 x=0
Answer:
q = 2
Step-by-step explanation:
Move all terms that don't contain q to the right side and solve.