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777dan777 [17]
4 years ago
13

The radius of a circle is 4 miles. What is the circle's area 3.14 for ​.

Mathematics
1 answer:
Firlakuza [10]4 years ago
6 0

Answer:

50.24

Step-by-step explanation:

4^2=16

16*3.14=50.24

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Step-by-step explanation:

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3 years ago
What is (1/4) / (6/7)<br> Please don’t just tell me the answer, please review the steps.
lbvjy [14]

Answer:

7/24 Is The Answer!

Step-by-step explanation:

Division of fractions is equivalent to multiplication by the reciprocal of the second fraction:

1/4 Divided by 6/7 = 1/4 ₓ 7/6

Once rearranged, multiply all of the numerators by each other. Do the same with the denominators and form a new fraction with these values:

1/4 times 7/6 = 7/24

The result Is

1/4 divided by 6/7 = 7/24

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3 years ago
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3 years ago
If x is a non-zero number and n is an integer, then x^-n is the reciprocal of x^n<br> True or False
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8 0
3 years ago
Read 2 more answers
In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent (Pew Research, June 5, 2014). An independe
enot [183]

Answer:

a)

n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2, in which z is related to the confidence level.

b) A sample size of 991 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In 16% of all homes with a stay-at-home parent, the father is the stay-at-home parent

This means that \pi = 0.16

a. What sample size is needed if the research firm's goal is to estimate the current proportion of homes with a stay-at-home parent in which the father is the stay-at-home parent with a margin of error of 0.03 (round up to the next whole number).

This is n for which M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = z\sqrt{\frac{0.16*0.84}{n}}

0.03\sqrt{n} = z\sqrt{0.16*0.84}

\sqrt{n} = \frac{z\sqrt{0.16*0.84}}{0.03}

(\sqrt{n})^2 = (\frac{z\sqrt{0.16*0.84}}{0.03})^2

n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2, in which z is related to the confidence level.

Question b:

99% confidence level,

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

n = (\frac{z\sqrt{0.16*0.84}}{0.03})^2

n = (\frac{2.575\sqrt{0.16*0.84}}{0.03})^2

n = 990.2

Rounding up

A sample size of 991 is needed.

8 0
3 years ago
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