All categories

2 years ago

Help picture below problem 8

Mathematics

1 answer:

liraira [26]2 years ago

5 0

Solution :-

Here, we have been given that lines f and g are parallel. Thus, the angle measuring 135° and ∠2 are vertically opposite angles.

And we know that vertically opposite angles measure same. Thus,

∠2 = 135°

Hope that helps ~~~

You might be interested in

I NEED HELP WITH THIS!

Ymorist [56]

9 is the answer for that problem

5 0

2 years ago

Read 2 more answers

Twice a number divid by 6 is 42

il63 [147K]

A number=x

2x/6=42
2x=252 by multiplying both sides by 6
x=126 by dividing both sides by 2 to isolate the variable

8 0

2 years ago

Read 2 more answers

What are the correct options

kondor19780726 [428]

The third one because each banner costs $16 and x is the number of banners, $32 is just a one time fee so there is no x.

5 0

3 years ago

Find the product: (x+9)(x-9) a 18 b. -81 C. - 18 d. x-64

Lilit [14]

Answer:

x^2 -81

Step-by-step explanation:

(x+9)(x-9)

FOIL

first x*x = x^2

outer -9x

inner 9x

last -9*9 = -81

Add them together

x^2 -9x+9x -81

Combine like terms

x^2 -81

5 0

3 years ago

Read 2 more answers

3x^2 - 4x = -2 Solve

amid [387]

Answer:

$x = \bigg \{\frac{ 2 - \sqrt{2} \: i }{3}, \: \: \frac{ 2 + \sqrt{2} \: i }{3} \bigg \}$

Step-by-step explanation:

$3 {x}^{2} - 4x = - 2 \\ 3 {x}^{2} - 4x + 2 = 0 \\ equating \: it \: with \\ a {x}^{2} + bx + c = 0 \\ a = 3 \: \: b = - 4 \: \: c = 2 \\ {b}^{2} - 4ac \\ = {( - 4)}^{2} - 4 \times 3 \times 2 \\ = 16 - 24 \\ = - 8 \\ \ {b}^{2} - 4ac < 0 \\ \therefore \: given \: quadratic \: equation \: have \: \\ imaginary \: solutios. \\ \\ x = \frac{ - b \pm \sqrt{{b}^{2} - 4ac } }{2a} \\ = \frac{ - ( - 4) \pm \sqrt{ - 8} }{2 \times 3} \\ = \frac{ 4 \pm 2\sqrt{2} \: i }{2 \times 3} \\ = \frac{ 2 \pm \sqrt{2} \: i }{3} \\ \therefore \: x = \frac{ 2 - \sqrt{2} \: i }{3} \: or \: x = \frac{ 2 + \sqrt{2} \: i }{3} \: \\ \\ x = \bigg \{\frac{ 2 - \sqrt{2} \: i }{3}, \: \: \frac{ 2 + \sqrt{2} \: i }{3} \bigg \}$

7 0

3 years ago