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horrorfan [7]
3 years ago
9

Plz solve this inequality

Mathematics
1 answer:
nasty-shy [4]3 years ago
8 0

Answer:

\{r | r \ge -3 \}

Step-by-step explanation:

7 - 9r - (r + 12) \le 25

Remember that to deal with the negative sign to the left of the parentheses, you must think of it as a -1 multiplying the parentheses, and you distribute the -1 by multiply each term inside the parentheses by -1. That changes all the signs inside the parentheses.

7 - 9r - r - 12 \le 25

Combine like terms on the left side.

-10r - 5 \le 25

Add 5 to both sides.

-10r \le 30

We now divide both sides by -10. Remember that when you divide both sides fo an inequality by a negative number, the inequality sign changes direction.

r \ge -3

Answer: \{r | r \ge -3 \}

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It costs $21.50 to enter an amusement park and $0.50 to ride a ride. You have $24. Write an equation that represents the number
zysi [14]

Answer:

24=0.5r+21.5

Step-by-step explanation:

y=mx+b

24= how much money you have

0.5= cost of each ride

r=number of rides you can ride

21.5= price it takes to enter

5 0
3 years ago
If c(x) = 5/(x - 2) d(x) = x + 3 , what is the domain of (co)(x) ?
frosja888 [35]

Answer:

Domain of (cd)(x) is all real numbers values except 2.

The value of (f/g)(5) is 270

Step-by-step explanation:

4 0
3 years ago
GH =x+7, HI= 2x - 6, and GI= 25. <br> Find the value of X
Fudgin [204]
Answer: x=8

Explanation: cause it is lol
3 0
3 years ago
Verify that the given vector field h is a gradient. Then calculate the line integral of h over the indicated curve C by finding
lukranit [14]

Answer:

f(x,y) = \frac{x^2 y^2}{2}

The value of the line integral is 2

Step-by-step explanation:

h(x,y) = xy^2 i + yx^2 j

Note that if you derivate the first part over the variable y and the second part over the variable x, then in both cases you obtain 2xy, therefore there must be a function f whose gradient is h, because the cross derivates are equal.

In order to find such f, you can calculate a primitive of both expressions, the first one over the variable x and the second one over the variable y.

A general primitive of xy² i (over x) is

f_1(x,y) = \frac{x^2y^2}{2} + a(y)

With a(y) a function that depends only on y. A general primitive of yx² j (over y) is

f_2(x,y) = \frac{x^2y^2}{2} + b(x)

With b(x) only depending on x

The function f(x,y) whose gradient is h is obtained by equaling the expressions of f₁ and f₂. f₁ and f₂ are equal when a(x) = b(x) = 0, therefore

f(x,y) = \frac{x^2y^2}{2}

note that

  • fx(x,y) = xy²
  • fy(x,y) = yx²

As we wanted. Lets find the endpoints of C

r(u) = u i + 2 u² j

r(0) = (0,0)

f(1) = (1,2)

Therefore,

\int\limits_C {xy^2} \, dx + {yx^2} \, dy = f((1,2)) - f((0,0)) = \frac{1^2 * 2^2}{2} - \frac{0^20^2}{0} = \frac{4}{2} - 0 = 2

The value of the line integral over C is 2.

3 0
4 years ago
Solve for x: -12x = -72
Ne4ueva [31]

Answer:

x=6

Step-by-step explanation:

6*12=72

6*-12=-72

8 0
3 years ago
Read 2 more answers
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