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ZanzabumX [31]
2 years ago
10

Error Analysis Your friend says that the volume of this sphere is 44.58

Mathematics
1 answer:
Maurinko [17]2 years ago
6 0

Answer:

  • the given dimension was used as the radius
  • 5.57 m³

Step-by-step explanation:

The volume of a sphere can be found using the formula ...

  V = 4/3πr³ . . . . . where r is the radius

__

The figure points to a diameter line and indicates 2.2 m. The arrowhead is in the middle of a radius line, making it easy to interpret the dimension as the radius of the sphere.

If 2.2 m is used as the radius, the volume is computed to be ...

  V = 4/3π(2.2 m)³ ≈ 44.58 m³

This agrees with your friend's volume, suggesting the diameter was used in place of the radius in the computation.

__

The correct volume, using 2.2 m as the diameter, is ...

  V = 4/3π(1.1 m)³ ≈ 5.57 m³

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Mr. Heath organizes a six-game tournament where players will
EleoNora [17]

9514 1404 393

Answer:

  (W, T, L, S) = (3, 2, 1, 4.1)

Step-by-step explanation:

For some number of wins (W), ties (T), and losses (L), the player's score will be ...

  score = 2.2W +0.25T -3L

For 3 wins, 2 ties, and 1 loss, the player's score is ...

  2.2(3) +0.25(2) -3(1) = 6.6 +0.5 -3 = 4.1

4 0
2 years ago
The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.
valina [46]

Answer:

A sample of 179 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.85}{2} = 0.075

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.075 = 0.925, so Z = 1.44.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

A previous study found that for an average family the variance is 1.69 gallon?

This means that \sigma = \sqrt{1.69} = 1.3

If they are using a 85% level of confidence, how large of a sample is required to estimate the mean usage of water?

A sample of n is needed, and n is found for M = 0.14. So

M = z\frac{\sigma}{\sqrt{n}}

0.14 = 1.44\frac{1.3}{\sqrt{n}}

0.14\sqrt{n} = 1.44*1.3

\sqrt{n} = \frac{1.44*1.3}{0.14}

(\sqrt{n})^2 = (\frac{1.44*1.3}{0.14})^2

n = 178.8

Rounding up

A sample of 179 is needed.

7 0
3 years ago
Use the digits 2,3,and 5 to create a fraction and a whole number with a product greater than 2
mylen [45]

Product is multiplication.

Since the answer needs to be greater than 2 either the fraction needs to be an improper fraction ( meaning the fraction would be greater than 1) or the whole number would need to be greater than 2.


One answer would be 5 x 2/3 = 3 1/3

3 0
3 years ago
Can anyone help me with this?
matrenka [14]

Answer:

\sqrt{7}

Step-by-step explanation:

Given

4\sqrt{7} - 10\sqrt{7} + 7\sqrt{7} ( add the coefficients of the terms )

= (4 - 10 + 7) \sqrt{7}

= 1\sqrt{7}

= \sqrt{7}

5 0
3 years ago
Calculate volume of hemisphere with radius 3.2 cm
Olin [163]

Answer:

V ≈ 68.63 cm³

Step-by-step explanation:

the volume (V) of a sphere is calculated as

V = \frac{4}{3}πr³

the volume of a hemisphere is half the volume of a sphere, so

V = \frac{1}{2} × \frac{4}{3} πr³ = \frac{2}{3} πr³ , then

V = \frac{2}{3} π × 3.2³

  = \frac{2}{3} π × 32.768

  ≈ 68.63 cm³ ( to 2 dec. places )

5 0
2 years ago
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