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liq [111]
3 years ago
13

How many tens are in 13.58

Mathematics
2 answers:
ivolga24 [154]3 years ago
7 0
13.58....contains 1 ten, 3 ones, 5 tenths, 8 hundredths
e-lub [12.9K]3 years ago
6 0
Tens - 1
ones - 3
decimal
<span>tenths - 5
</span><span>hundredths - 8</span>

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Intersecting lines that are formed as a right angle are defined as?
Natalija [7]

Answer:

Perpendicular

Step-by-step explanation:

Definition of perpendicular lines:

Lines that intersect forming a right angle are perpendicular lines.

4 0
3 years ago
Read 2 more answers
use the matrix tool to solve the system of equations enter the answer as an ordered pair. 8x+5y=9 -x+y=7
Dimas [21]

Answer:

x = -44/13

y = -65/13

Step-by-step explanation:

Using matrix form means using the crammers rule

The matrix form of the expression is written as;

\left[\begin{array}{ccc}8&5\\-1&1\\\end{array}\right] \left[\begin{array}{ccc}x\\y\\\end{array}\right] = \left[\begin{array}{ccc}9\\7\\\end{array}\right]

AX = B

taking the determinant of A;

|A| = 8(1) - 5(-1)

|A| = 8 + 5

|A| = 13

After replacing the first row with the column matrix;

A_x =\left[\begin{array}{ccc}9&5\\7&-1\\\end{array}\right]

|Ax| = 9(-1)-5(7)

||Ax| = -9 - 35

|Ax| = -44

x = |Ax|/|A|

x = -44/13

similarly for y

A_x =\left[\begin{array}{ccc}8&9\\-1&7\\\end{array}\right]

|Ay| = 8(7)+9

|Ay| = 56+9

|Ay| = 65

y = |Ay|/|A|

y = -65/13

6 0
3 years ago
A 25-foot ladder is placed against a building. The bottom of the ladder is 7 feet from the building. If the top of the ladder sl
algol [13]

Answer:

As per the statement:

A 25-foot ladder is placed against a building. The bottom of the ladder is 7 feet from the building.

⇒Length of the ladder against a building = 25 foot

and Length of the bottom of the ladder from the building= 7 feet.

You had Before the slip.

Let x be the height of the building where ladder hits the building

By Pythagoras theorem:

\text{Hypotenuse side}^2=\text{Perpendicular}^2+\text{Base}^2

Here, Perpendicular side = Height of the building = x ,  Base = Length of the bottom of the ladder from the building = 7 foot and Hypotenuse side = 25 foot

Substitute the value to solve for x;

25^2=x^2+7^2

625=x^2+49

or

x^2 = 625-49 = 576

x = \sqrt{576} = 24 foot.

⇒Height of the building = 24 foot

Now, if the ladder slips down 4 feet.

You had after slip

⇒Now, the height of the building becomes = 24-4 = 20 foot.

Let y be the distance from the building wall

then by Pythagoras theorem;

y^2+20^2 = 25^2

y^2+400 =625

y^2 = 625-400 = 225

y=\sqrt{225} = 15 foot.

We have to find how many feet will the bottom slide out.

Since, Originally the distance of the bottom from the building = 7 foot

And now, the distance is = 15 foot.

The bottom slide out will be = 15 - 7 =8 foot

Therefore, 8 feet will the bottom slide out

6 0
3 years ago
Students collected 600 cans for the canned food drive.
BartSMP [9]

Answer:

they'll need 200 more cans

5 0
3 years ago
Sergio ate 3.5 cookies. Each cookie contained 5.7 grams of sugar. How many grams of sugar did Sergio eat?
FrozenT [24]
I’ll get it correct here :)

He ate 19.95 grams of sugar.

3.5 x 5.7 = 19.95
5 0
3 years ago
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