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Anika [276]
3 years ago
14

Solve 2-6(1-x)=6-4(-x-2) for x

Mathematics
1 answer:
OLEGan [10]3 years ago
4 0

Answer:

x = 9

Step-by-step explanation:

Simplifying

2 + -6(1 + -1x) = 6 + -4(-1x + -2)

2 + (1 * -6 + -1x * -6) = 6 + -4(-1x + -2)

2 + (-6 + 6x) = 6 + -4(-1x + -2)

Combine like terms: 2 + -6 = -4

-4 + 6x = 6 + -4(-1x + -2)

Reorder the terms:

-4 + 6x = 6 + -4(-2 + -1x)

-4 + 6x = 6 + (-2 * -4 + -1x * -4)

-4 + 6x = 6 + (8 + 4x)

Combine like terms: 6 + 8 = 14

-4 + 6x = 14 + 4x

Solving

-4 + 6x = 14 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.

-4 + 6x + -4x = 14 + 4x + -4x

Combine like terms: 6x + -4x = 2x

-4 + 2x = 14 + 4x + -4x

Combine like terms: 4x + -4x = 0

-4 + 2x = 14 + 0

-4 + 2x = 14

Add '4' to each side of the equation.

-4 + 4 + 2x = 14 + 4

Combine like terms: -4 + 4 = 0

0 + 2x = 14 + 4

2x = 14 + 4

Combine like terms: 14 + 4 = 18

2x = 18

Divide each side by '2'.

x = 9

Simplifying

x = 9

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max2010maxim [7]

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

\displaystyle \sec(\theta)=\frac{u}{10}

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}

By substitutition:

\displaystyle= \sin(2\theta)

Using an double-angle identity:

=2\sin(\theta)\cos(\theta)

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)

Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

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What is 1/8 +(-3/16) A. 4/2 B. 5/16 C.-5/16 D. -1/16
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Answer:

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Step-by-step explanation:

1/8 +(-3/16) = -1/16

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