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masha68 [24]
3 years ago
12

Need help with this Find each indicated measure for circle O

Mathematics
1 answer:
Otrada [13]3 years ago
8 0

Answer:

Angle A = 41, Arc CE = 42, Angle C = 41, Angle D = 40, Angle ABE = 61

Step-by-step explanation:

Angle A = Arc BD/2  (Inscribed Angle)

Angle A = 82/2

Angle A = 41

Arc CE = 2 x Angle CEB (Inscribed Angle)

Arc CE = 2 x 21

Arc CE = 42

Angle C = Arc BD/2 (Inscribed Angle)

Angle C = 82/2

Angle C = 41

Angle D = Arc AC/2  (Inscribed Angle)

Angle D = 80/2

Angle D = 40

Angle ABE = Arc AE/2

Angle ABE = Arc AC + Arc CE/2

Angle ABE = 122/2

Angle ABE = 61

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Find the discriminant and determine the nature of the roots to the quadratic equation
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№17
x^{2} +6x-7=0 \\ D=6 ^{2} -4*(-7)=36+28=64=8 ^{2}  \\  \\  x_{1} = \frac{-6+8}{2} =1 \\  \\  x_{2} = \frac{-6-8}{2} =-7
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№18
2 x^{2} -3x+4=3 \\ 2 x^{2} -3x+4-3=0 \\ 2 x^{2} -3x+1=0 \\  \\ D= -3 ^{2} -4*2=9-8=1 \\  \\  x_{1} = \frac{3+1}{2*2} = \frac{4}{4} =1 \\  \\  x_{2} = \frac{3-1}{2*2} = \frac{2}{4} =0.5
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№19
2 x^{2} -4x-5=0 \\  D=-4 ^{2} -4*2*(-5)=16+40=56 \\  \\  x_{1}= \frac{4+ \sqrt{56} }{2*2}  = \frac{4}{4} + \sqrt{ \frac{56}{16} } =1+ \sqrt{3.5}  \\  \\  x_{2} = \frac{4- \sqrt{56} }{2*2} = \frac{4}{4} -  \sqrt{ \frac{56}{16} } =1- \sqrt{3.5} 

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4 years ago
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Nonamiya [84]
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4 0
4 years ago
Find the side of a cube whose surface area is 600cm²
expeople1 [14]

Answer:

<em><u>10 cm</u></em>

Explanation:

Surface area of cube = 600 cm^2

Side of a cube = ?

Formula:

Total S.A of cube =  6 x (side of cube)^2

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600 cm2 =  6 . x^2

x^2  = 600 / 6

x^2 = 100

x = 10 cm

<em>The required side of a cube = 10 cm</em>

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8 0
3 years ago
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