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3 years ago

How can the ph of antiacid table de determine in laboratory

Chemistry

1 answer:

jenyasd209 [6]3 years ago

8 0

Answer:

Antacids are bases that react stoichiometrically with acid. The number of moles of acid that can be neutralized by a single tablet of a commercial antacid will be determined by back titration.

Correct me if i'm wrong, Hope This helps

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A cubic object has a volume of 250 cm. What is its density if its mass is 5 points<br> 257.3 g?

ira [324]

Answer:

<h3>The answer is 1.03 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass = 257.3 g

volume = 250 cm³

We have

$density = \frac{257.3}{250} \\ = 1.0292$

We have the final answer as

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8 0

3 years ago

Why isn't air travel based on hydrogen popular today? A.Hydrogen is very expensive B. Hydrogen is difficult to find C. Hydrogen

Butoxors [25]

The answer is c. hydrogen is flammable and dangerous

4 0

3 years ago

Read 2 more answers

If 16.8 mL of the analyte H2C2O4 (oxalic acid) is titrated with 0.501 M KOH to 13.54 mL, determine the mass of the analyte.

Neko [114]

Answer:

Mass of Analyte H2C2O4 = 18.18 grams

Explanation:

The balanced equation is:

$H_{2}C_{2}O_{4}+2KOH\rightarrow K_{2}C_{2})_{4}+H_{2}O$

The Molarity of Oxalic acid needed can be determined using: $M_{1}V_{1}=M_{2}V_{2}$

Here M1 = Molarity of Oxalic acid

V1 = Volume of oxalic acid

M2 = Molarity of KOH and V2 = Volume of KOH

M1 = ? , V1 = 16.8 mL , M2 = 0.501 M , V2 = 13.54 mL

Put the values and solve for M2,

$M_{1}V_{1}=M_{2}V_{2}$

$2\times M_{1}(16.8)=0.501\times 13.54$

We are multiplying by 2 because , 1 H2C2O4 needs 2 KOH

$M_{1}=\frac{0.501\times 13.54}{2\times 16.8}$

$M_{1}=0.202M$

Hence Molarity of H2C2O4 =

0.202 M

Molar mass = H2C2O4 = 2x1 +2x12 + 4x16

= 2+24+64 = 90 gram

$Mole =molarity\times Molar\ mass$

$Moles=0.202\times 90$

18.18 gram

8 0

3 years ago

an ideal gas is at a pressure 1.00 x 10^5 N/m^2 and occupies a volume 11.00 m^3. If the gass is compressed to a volume of 1.00 m

bogdanovich [222]

Answer:

$P_2=1.1x10^6Pa$

Explanation:

Hello.

In this case, we can solve this problem by applying the Boyle's law which allows us to understand the pressure-volume behavior as a directly proportional relationship:

$P_1V_1=P_2V_2$