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damaskus [11]
3 years ago
15

How can the ph of antiacid table de determine in laboratory ​

Chemistry
1 answer:
jenyasd209 [6]3 years ago
8 0

Answer:

Antacids are bases that react stoichiometrically with acid. The number of moles of acid that can be neutralized by a single tablet of a commercial antacid will be determined by back titration.

Correct me if i'm wrong, Hope This helps

Favor(Brainliest)

#Carryonlearning

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How many moles of silicon (Si) are in 1.50 x 1023 atoms Si?
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Answer:

1534.5

Explanation:

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8 0
3 years ago
When calcium hydroxide powder is placed into a hydrochloric acid solution, aqueous calcium chloride and water are formed?
Vanyuwa [196]
<span>Answer: yes, when calcium hydroxide powder is placed into a hydrochloric acid solution, aqueous calcium hydroxide and water are formed.
</span>
<span /><span /><span>
Explanation:


</span><span>1) Calcium hydroxide is a base whose chemical formula is: Ca(OH)₂</span>
<span /><span>
2) Hydrochloric acid is the acid with chemical formula HCl


</span><span>3) Acids and bases react in a double replacement reaction forming salt plus water: Acid + Base → salt + water
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<span /><span /><span>
4) The specific chemical equation for these reactants is:


</span><span>Ca(OH)₂ (s) + 2HCl(aq) → CaCl₂ (aq) + 2H₂O(l)</span>
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</span><span>5) CaCl₂ is calcium chloride, a salt,  and H₂O is water
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5 0
3 years ago
Read 2 more answers
How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 ∘C to 6 ∘C? (Assume the density o
Rashid [163]

Answer:

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

Explanation:

Heat gain by ice = Heat lost by water

Thus,  

Heat of fusion + m_{ice}\times C_{ice}\times (T_f-T_i)=-m_{water}\times C_{water}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

Heat of fusion + m_{ice}\times C_{ice}\times (T_f-T_i)=m_{water}\times C_{water}\times (T_i-T_f)

Heat of fusion = 334 J/g

Heat of fusion of ice with mass x = 334x J/g

For ice:

Mass = x g

Initial temperature = 0 °C

Final temperature = 6 °C

Specific heat of ice = 1.996 J/g°C

For water:

Volume = 353 mL

Density (\rho)=\frac{Mass(m)}{Volume(V)}

Density of water = 1.0 g/mL

So, mass of water = 353 g

Initial temperature = 26 °C

Final temperature = 6 °C

Specific heat of water = 4.186 J/g°C

So,  

334x+x\times 1.996\times (6-0)=353\times 4.186\times (26-6)

334x+x\times 11.976=29553.16

345.976x = 29553.16

x = 85.4197 kg

Thus,  

<u>The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg</u>

7 0
4 years ago
The energy levels of the positive ions that have just a single electron, like He , Li2 , or Be3 , etc., follow the formula Bohr
Sidana [21]
The answer is false. Hope that helps
3 0
3 years ago
In a ________ reaction, a single uncombined element replaces another element in a compound. synthesis double displacement single
kicyunya [14]
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  Single   replacement   is  type  of chemical  reaction  where  an  element  react  with   a  compound  and take   the  place  of   another element  in  that  compound.
example  of  this  type  of  reaction  is 
Zn+ 2HCl  ----->  Zncl2  +  H2
7 0
3 years ago
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