Answer:
yes it has
Step-by-step explanation:
The numerators of the eqations equates themselves likewise the denominator
numerators=10
denominators=3
16. 5x^3 y^-5 • 4xy^3
20x^4y^-2
20x^4 • 1/y^2
=20x^4/y^2
17. -2b^3c • 4b^2c^2
= -8b^5c^3
18. a^3n^7 / an^4 (a^3 minus a = a^2 same as n^7 minus n^4 = n^3)
=a^2n^3
19. -yz^5 / y^2z^3
= -z^2/y
20. -7x^5y^5z^4 / 21x^7y^5z^2 (divide -7 to 21 and minus xyz)
= -z / 3x^2
21. 9a^7b^5x^5 / 18a^5b^9c^3
=a^2c^2 / 2b^4
22. (n^5)^4
n ^5 x 4
=n^20
23. (z^3)^6
z ^3 x 6
=z^18
Answer:
3x - 11
Step-by-step explanation:
x + 5/ 3x-11
3x - 11 is the quotient
Answer:
well...............................................................i think i just st0le points
Step-by-step explanation:
sowwy
<h3>
Answer: E) x^5</h3>
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Explanation:
We simply take half of the exponent 10 to get 5. This applies to square roots only.
So the rule is 
A more general rule is
![\sqrt[n]{a^b} = a^{b/n}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Eb%7D%20%3D%20a%5E%7Bb%2Fn%7D)
If n = 2, then we're dealing with square roots like with this problem. In this case, a = x and b = 10.
