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Kobotan [32]
3 years ago
7

Let f(x) = x2 − 8x + 5. Find f(−1).

Mathematics
2 answers:
Ulleksa [173]3 years ago
5 0
F(x)=x2-8x+5
=-6x+5
f(-1)= 6(-1)+5
=-6+5
=-1
Westkost [7]3 years ago
3 0
F(x) = x^2 - 8x + 5

f(-1) = -1^2 - 8(-1) + 5
f(-1) = 1 + 8 + 5
f(-1) = 14 <==
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Kyle is a salesman. His monthly earnings include a fixed monthly salary and a commission that is a fixed percentage of his total
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Answer:

Kyle’s fixed monthly salary in dollars is $1800

Step-by-step explanation:

let a be the fixed monthly salary

let b% represent the fixed percentage of sales

a+(b%*15000)=2550

a+(b%*25000)=3050

a+(b/100*15000)=2550

a+150b=2550

a+(b/100*25000)=3050

a+250b=3050

now we have

a+150b=2550

a+250b=3050

let subtract a+150b=2550 from a+250b=3050

100b=500

b=500/100=5%

then a+(5%*15000)=2550

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8 0
3 years ago
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Yuliya22 [10]

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7 0
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5 0
2 years ago
Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


5 0
3 years ago
Please help not sure what to do
yawa3891 [41]

Answer:

3x12 theres 3 cirs and 6÷4 so 3x12

7 0
3 years ago
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