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vlabodo [156]
2 years ago
8

How to find the area of an equilateral triangle inside a circle

Mathematics
1 answer:
Irina18 [472]2 years ago
6 0

Answer:

Step-by-step explanation:

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if you save three pennies on January 1, six pennies on January 2, nine pennies on January 3, and continue this pattern for one y
Katarina [22]

Answer:

2003.85

Step-by-step explanation:

I realize I'm a year late, but the math of the previous answer was so terrible I'm honestly too horrified to let this be.

You have save by an increasing amount of 3 pennies per day. You start with 3 and build from that, each day, for 365 days. First, you must figure out what amount of pennies you shoved into your account on the final 365th day.

An= a1+(n-1)d

An=term you want

a1= term you begin with

n= term you want

d= constant amount

A_365= 3 + (365-1)*3

A_365= 1095

Arithmetic Sum: Sn = N/2 (a1 + an)

365/2 * (3 + 1095) = 200385.

This means you've invested a total of 200385 PENNIES after 365 days.

The question asks for dollars, not your rusting lincoln's.

As (I hope) you know, 1 Dollar = 100 pennies

200385 pennies/100 = 2003.85.

This means you have $2003.85 in your account by the conclusion of the 365th day.

4 0
3 years ago
The expression means the product of 5 and the difference of three times r minus 10. If r = 4, the value of the expression is .
Morgarella [4.7K]

Answer:

10

Step-by-step explanation:

"three times r" = 3r

"three times r minus ten" = 3r - 10

"product of 5 and the difference of three times r minus ten"

= 5 (3r - 10)

given that r = 4,

the expression becomes

5 (3r - 10)

= 5 [3(4) - 10]

= 5 [12 - 10]

= 5 (2)

= 10

4 0
3 years ago
Suppose that 13 inches of wire costs 78 cents. At the same rate, how much (in cents) will 37 inches of wire cost?
Neko [114]
78/13 = 6 cents per inch
37 * 6 = 222
5 0
3 years ago
Read 2 more answers
FAST PLEASE
meriva

Answer:

A. 5

Step-by-step explanation:

y2 - y1 / x2 - x1

5 - -5 / 3 -1 = 10/2 = 5

7 0
3 years ago
Expanding Logarithmic Expressions In Exercise, use the properties of logarithms to rewrite the expression as a sum, difference,
Leya [2.2K]

Answer:  \dfrac{1}{3}[\ln (x+1)+\ln(x-1)]

Step-by-step explanation:

Properties of logarithm :

  1. \log (ab)= \log a+\log b
  2. \log(\dfrac{a}{b})=\log a-\log b
  3. \log a^n= n\log a

The given expression in terms of Natural log : \ln (x^2 - 1)^{\frac{1}{3}}

This will become \dfrac{1}{3}\ln (x^2 - 1)      [ By using Property (3)]

=\dfrac{1}{3}\ln (x^2-1^2)

=\dfrac{1}{3}\ln ((x+1)(x-1))   [\because a^2-b^2=(a+b)(a-b)]

=\dfrac{1}{3}[\ln (x+1)+\ln(x-1)]   [ By using Property (1)]

Hence, the simplified expression becomes \dfrac{1}{3}[\ln (x+1)+\ln(x-1)] .

5 0
3 years ago
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