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barxatty [35]
3 years ago
8

Uma wants to buy a video game system for $400. She has $50 and is saving $25 each week. Solve the equation 25w + 50 = 400 to fin

d how many weeks w it will take Uma to save enough to buy the system.
Mathematics
2 answers:
Sonja [21]3 years ago
8 0
Move all terms that don't contain <span>ww</span> to the right side and solve.<span>
w=<span>14

Hope this helps,

kwrob

</span></span>
Agata [3.3K]3 years ago
5 0
First take away fifty from both sides
25w = 350
Divide 25 from both sides
Answer is: w = 14


So, it will take Uma 14 weeks to save enough money to but the video game system.




Hope that helps!!!

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Answer:

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Step-by-step explanation:

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Questions 2-7 will all be in regards to this data set:Observation X Y1 20 302 23 353 28 404 26 385 24 376 32 457 35 508 24 349 3
Tomtit [17]

Answer:

r =0.4437

Step-by-step explanation:

We have the follwoing dataset:

X: 20,23,53,4,24,32,35,24,31,23

Y: 30,35,40,38,37,45,50,34,42,32

n=10

The correlation coefficient is a "statistical measure that calculates the strength of the relationship between the relative movements of two variables". It's denoted by r and its always between -1 and 1.

And in order to calculate the correlation coefficient we can use this formula:

r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}  

For our case we have this:

n=10 \sum x = 269, \sum y = 383, \sum xy = 10609, \sum x^2 =8645, \sum y^2 =15007  

Th excel figure attached shows the calculations for each sum.

r=\frac{10(10609)-(269)(383)}{\sqrt{[10(8645) -(269)^2][10(15007) -(383)^2]}}=0.4437  

So then the correlation coefficient would be r =0.4437

3 0
3 years ago
Consider the following function. f(x) = (x + 5)2/3 (a) Find the critical numbers of f. (Enter your answers as a comma-separated
Olin [163]

Answer:

See explaination

Step-by-step explanation:

Please kindly check attachment for detailed and step by step solution of the given problem.

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vovangra [49]

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Step-by-step explanation:

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3 years ago
Read 2 more answers
Guys, Can you please help me with these questions
MakcuM [25]

Answer:

a) w^{13} x^{5} y^{6}

b) \frac{x}{3y^{6} }

Step-by-step explanation:

a) (w^{2} xy^{3} )^{2}(w^{3}x )^{3}

1. Distribute the second power (2) outside the first pair of parenthesis:

(w^{2(2)} x^{2} y^{3(2)} )

= w^{4} x^{2} y^{6} (w^{3}x )^{3}

2. Distribute the third power (3) outside the second pair of parenthesis:

(w^{3(3)} x^{3} )

= w^{4} x^{2} y^{6} w^{9} x^{3}

3. Combine like terms:

w^{13} x^{5} y^{6}

--------------------------------------------

b) \frac{2x^{2} y^{5} }{6xy^{11} }

1. Factor the number 6 (= 2 · 3):

\frac{2x^{2} y^{5} }{2(3)xy^{11} }

2. Cancel the common factor (2):

\frac{x^{2} y^{5} }{3xy^{11} }

3. Cancel out xy^{5} in the numerator an denominator:

\frac{x}{3y^{6} }

hope this helps!

4 0
2 years ago
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