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2 years ago

Please help me? it is school related i promise

Mathematics

2 answers:

nadya68 [22]2 years ago

6 0

Answer:

$96.25

Step-by-step explanation:

In the morning, this worker was in for a total of 4 hours. Since the wage is $11/hr, we have to multiply 4 by 11.

11 * 4 = 44

In the afternoon, they worked for 4 hours and 45 minutes. Now, we have to multiply 4 3/4 (which is the fraction form of 4 hours and 45 mins) by 11.

11 * 4 3/4 = 52.25

Now, to find the total pay, we add together both the morning and afternoon pays.

44 + 52.25 = 96.25

Therefore, the total pay is $96.25

I hope this helps!! Have a lovely day!! :)

tester [92]2 years ago

4 0

Answer:

$96.25

Step-by-step explanation:

Hours worked in the morning = 12:00 - 8:00

= 4 hours

Hours worked in the afternoon = 17:30 - 12:45

= 4 hours 45 minutes

Total hours worked = 4:00 + 4:45

= 8 hours 45 minutes

$=8\dfrac{45}{60} \ hours\\\\= 8\dfrac{3}{4}\\\\\\= \dfrac{35}{4} hours$

Wage = $\dfrac{35}{4}*11$

= $96.25

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nikdorinn [45]

I need to answer to ask

6 0

3 years ago

Read 2 more answers

The common difference in an arithmetic sequence is –2 and the first term is 47. What is the 29th term?

BlackZzzverrR [31]

An arithmetic sequence is an ordered list of numbers where the next number is found by adding on to the last number (ex: 2,5,8,11... is a sequence where 3 is added on to find the next number).

The equation for an arithmetic sequence is
$A_{n}=A_{1}+(n-1)d$

$A_{n}$ is the "n-th" number in the sequence (ex: is the first term in the sequence)
d is the number you add (common difference) to find the next number
The first number in the sequence is 47 so $A_{1}=47$
d=-2 because the question gives you that

$A_{n}=A_{1}+(n-1)d$
 $A_{29}=47+(29-1)(-2)$
 $A_{29}=47+(28)(-2)$
 $A_{29}=47+-56$
 $A_{29}=-9$

The answer is A. -9.

 

The answer is C. 158

For the second one, it gives you $A_{1}=4$ and $A_{}=18$
You can use this to find d

 $A_{n}=A_{1}+(n-1)d$
 $A_{3}=4+(3-1)d$
 $18=4+(3-1)d$
 $18=4+2d$
 $14=2d$
 $7=d$

Now you can just solve using the equation normally.
 $A_{n}=A_{1}+(n-1)d$
 $A_{23}=4+(23-1)(7)$
 $A_{23}=4+(22)(7)$
 $A_{23}=4+154$
 $A_{23}=158$

The answer is C. 158

8 0

4 years ago

Read 2 more answers

A structural steel fabricator cuts 25 pieces each 16.2 centimeters long from a 6.35-meter length

Daniel [21]

Answer: 2.2 meters

Step-by-step explanation:

The data is:

The initial piece is 6.35 meters long.

We cut 25 pieces of 16.2cm each, so in pieces only we have:

25*16.2cm = 405cm

1m = 100cm

Then: 405cm = (405/100) m = 4.05m

And each time that we cut a piece, we have 4mm of waste.

Then we have 25 times the 4mm of waste, this means that the total waste is:

4mm*25 = 100mm

and 1000mm = 1m

100mm = (100/1000) m = 0.1m

So the total amount that was cut is:

4.05m + 0.1m = 4.15m

The length in the channel iron will be: 6.35m - 4.15m = 2.2 meters

7 0

3 years ago

A rectangular plot of farmland will be bounded on one side by a river and on the other three sides by a single-strand electric

larisa86 [58]

Answer:

525 x 1,050

A = 551,250 m²

Step-by-step explanation:

Let 'L' be the length parallel to the river and 'S' be the length of each of the other two sides.

The length of the three sides is given by:

$2S+L=2,100\\ L=2100-2S$

The area of the rectangular plot is given by:

$A=S*L\\A=S(2100-2S)\\A=2100 S -2S^2$

The value of 'S' for which the area's derivate is zero, yields the maximum total area:

$\frac{dA(S)}{dS}=\frac{d(2100 S -2S^2)}{dS}\\0= 2100 - 4S\\S=525$

Solving for 'L':

$L=2100-(2*525)\\L=1,050$

The largest area enclosed is given by dimension of 525 m x 1,050 and is:

$A = 525*1,025\\A=551,250\ m^2$

5 0

4 years ago

The realtor and her clients do not know the average home sale price for all of Guelph (500 was actually just a guess). However,

strojnjashka [21]

Answer:

a) The 99% confidence interval would be given by (346.708;453.292)

b) The 99% confidence interval would be given by (338.445;461.555)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=400$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=80$ represent the population standard deviation

n=15 represent the sample size

2) Part a

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that $z_{\alpha/2}=2.58$

Now we have everything in order to replace into formula (1):

$400-2.58\frac{80}{\sqrt{15}}=346.708$

$400+2.58\frac{80}{\sqrt{15}}=453.292$

So on this case the 99% confidence interval would be given by (346.708;453.292)

3) Part b

For this case we don't know the population deviation so we need to use the t distribution instead the normal standard distribution.

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

We need to find the degrees of freedom first df=n-1=15-1=14

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that $t_{\alpha/2}=2.98$

Now we have everything in order to replace into formula (1):

$400-2.98\frac{80}{\sqrt{15}}=338.445$

$400+2.98\frac{80}{\sqrt{15}}=461.555$

So on this case the 99% confidence interval would be given by (338.445;461.555)

4 0

3 years ago