Write the equation for a line that contains the points (3,4) and (3,9)

Mathematics

1 answer:

SOVA2 [1]3 years ago

7 0

Answer:

Step-by-step explanation:

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Misha wrote the quadratic equation 0=-x2+4x-7 in standard form. what is the value of c in her equation

Masteriza [31]

Answer:

Final answer is c=-7.

Step-by-step explanation:

Given equation is $0=-x^2+4x-7$ .

Now question says that Misha wrote the quadratic equation 0=-x2+4x-7 in standard form. Now we need to find about what is the value of c in her equation.

We know that standard form of quadratic equation is given by $ax^2+bx+c=0$ .

compare given equation with the standard form, we find that -7 is written in place of +c

so that means +c=-7

or c=-7

Hence final answer is c=-7.

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3 years ago

Solving Multi-Step Equations

KengaRu [80]

$1.\\2n+3n+7=-41\\5n=-41-7\\5n=-48\\n=-48:5\\\boxed{n=-9.6}\\------------------\\2.\\2x-5x+6.3=-14.4\\-3x=-14.4-6.3\\-3x=-20.7\\x=(-20.7):(-3)\\\boxed{x=6.9}\\------------------$

$3.\\2z+9.75-7z=5.15\\-5z=5.15-9.75\\-5z=-4.6\\z=(-4.6):(-5)\\\boxed{z=0.92}\\------------------\\4.\\3h-5h+11=17\\-2h=17-11\\-2h=6\\h=6:(-2)\\\boxed{h=-3}\\------------------$

$5.\\2t+8-t=-3\\t=-3-8\\\boxed{t=-11}\\------------------\\6.\\6a-2a=-36\\4a=-36\\a=-36:4\\\boxed{a=-9}\\------------------$

$7.\\3c-8c+7=-18\\-5c=-18-7\\-5c=-25\\c=(-25):(-5)\\\boxed{c=5}\\------------------\\8.\\7g+14-5g=-8\\2g=-8-14\\2g=-22\\g=-22:2\\\boxed{g=-11}\\------------------$

$9.\\2b-6+3b=14\\5b=14+6\\5b=20\\b=20:5\\\boxed{b=4}\\------------------\\10.\\2(a-4)+15=13\\2a-8=13-15\\2a=-2+8\\2a=6\\a=6:2\\\boxed{a=3}\\------------------$

$11.\\7+2(a-3)=-9\\2a-6=-9-7\\2a=-16+6\\2a=-10\\a=-10:2\\\boxed{a=-5}\\------------------\\12.\\13+2(5c-2)=29\\10c-4=29-13\\10c=16+4\\10c=20\\c=20:10\\\boced{c=2}$

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3 years ago

Please help me with this math

motikmotik

The answer must be 2.333333333 × 10^5

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3 years ago

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Complete the equationof the line whose slope is -2 and y-intercept is (0,-8)

zmey [24]

Answer:hope I ain’t latee

Step-by-step explanation: