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3241004551 [841]
3 years ago
14

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

Mathematics
1 answer:
Brums [2.3K]3 years ago
6 0

\qquad\qquad\huge\underline{{\sf Answer}}♫

Let's solve ~

Surface area of Cylinder :

\qquad \sf  \dashrightarrow \:2\pi r(r + h)

\qquad \sf  \dashrightarrow \:2  \pi \times 5(5 + 4)

\qquad \sf  \dashrightarrow \:10 \pi(9)

\qquad \sf  \dashrightarrow \:90 \pi

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Dwayne brought 5 yards of wrapping paper how many inches of wrapping paper did he buy
Mademuasel [1]
It's 180 inches of wrapping paper.
8 0
3 years ago
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Flying against the wind, an airplane travels 7520 kilometers in 8 hours. Flying with the wind, the same plane travels 6500 kilom
bezimeni [28]

Answer:

Rate of plane in still air = 1120 km/h

Rate of wind = 180 km/h

Step-by-step explanation:

Let the rate (speed) of the plane in still air = u km/h

Let the rate (speed) of the wind = v km/h

Formula for speed is:

Speed = \dfrac{Distance}{Time}

Given that against the wind, airplane travels 7520 km in 8 hours.

The speed against the wind will be slower so,

Against the wind, speed = (u -v ) km/h

Using above formula:

(u-v) = \dfrac{7520}{8} km/h\\(u-v) = 940 km/h ..... (1)

Given that with the wind, airplane travels 6500 km in 5 hours.

The speed with the wind will be faster so,

With the wind, speed = (u +v ) km/h

Using above formula:

(u+v) = \dfrac{6520}{5} km/h\\(u+v) = 1300 km/h ..... (2)

Adding (1) and (2) to solve for u and v:

2u = 2240\\\Rightarrow u = 1120\ km/h

Putting u in (1):

1120-u=940\\\Rightarrow u = 180\ km/h

So, the answers are:

<em>Rate of plane in still air = 1120 km/h</em>

<em>Rate of wind = 180 km/h</em>

<em></em>

6 0
3 years ago
Use the slope or distance formula to determine the most precise name for the figure A(-3,-7) B(2,-3) C(9,4) D(4,0)
Kamila [148]
If u just give me my fricking points its 91
7 0
3 years ago
The weight of an object on the moon is
Tanzania [10]

Answer:

40 2/5Ibs or 40\frac{2}{5} lbs

Step-by-step explanation:

Let weight of object on the moon be represented = Wm

weight of object on the Earth = We

In the above question, we are told:

The weight of an object on the moon is

5 of its weight on Earth.

Hence, mathematically, this is represented as:

 5Wm = We

If a moon rock weighs 202 lbs on Earth

5Wm = 202lbs

Wm = 202lbs/5

Wm = 40\frac{2}{5}Ibs

Therefore, the moon rock weighs 40\frac{2}{5}Ibs on the moon.

7 0
3 years ago
Yung bought $4.60 worth of bubble gum. Each piece of gum cost $0.10. How many pieces of bubble gum did Yung buy?
Readme [11.4K]

<u><em>Answer:</em></u>

Yung bought 46 pieces of bubble gum for $4.6

<u><em>Explanation:</em></u>

We are given that each piece of gum cost $0.1 and that he spent $4.6 on gums

<u>To get the number of gums he bought, we will simply use cross multiplication as follows:</u>

1 piece .........................> 0.1

x pieces ......................> 4.6

<u>Therefore:</u>

x = \frac{4.6*1}{0.1}= 46 pieces of gum

Hope this helps :)

4 0
3 years ago
Read 2 more answers
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