put the decimal in the multiplication problem in the exact same point under the line then multiply as normal and you should get 152.6 meaning $152.60
Answer:
A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error of the interval is given by:
In this problem, we have that:
99.5% confidence level
So , z is the value of Z that has a pvalue of , so .
Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?
This is n when M = 0.07. So
A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
Answer:
2a (3-4a)
Step-by-step explanation:
(2a+1)-4a(2a+1)+4a
2a+1-8a²-1+4a
= 2a+4a-8a²
=6a-8a²
= 2a(3-4a)