The value of n is 4 and yz is 1 if y is between x and z i.e. if y, x and z are collinear points.
According to the given question.
We have some linear equations.
xy = 4n + 3
yz = 2n - 7
and
xz = 20
Since, y is between x and z. Which means y, x and z are collinear points.
Therefore,
xy + yz = xz
⇒ 4n + 3 + 2n - 7 = 20
⇒ 6n -4 = 20
⇒ 6n = 20 + 4
⇒ 6n = 24
⇒ n = 24/6
⇒ n = 4
Therefore,
yz = 2n - 7 = 2(4) - 7 = 8- 7 = 1
Hence, the value of n is 4 and yz is 1 if y is between x and z i.e. if y, x and z are collinear points.
Find out more information about collinear points here:
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Principal = 109,000
Return - 9,920
Return = (principal x rate x time)/100
X = the amount invested at 12%
Then 102000- x = the amount invested at 8%
9920 = (x*12)/100 + (109000-x*8)100
x = 30,000
a) 30,000 is invested at 12%
79,000 is invested at 8%
b) The 12% investment is riskier so if all the money was in that account the investor could lose all his money.
The answers should be:
A) 6n-4
B) -4n+25
