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Vera_Pavlovna [14]

2 years ago

12

The tree diagram shows he possible win/loss paths for a basketball team playing in a tournament. Harris High School loses 1 game

in the tournament. How many ways could this happen?

1 answer:

SpyIntel [72]2 years ago

3 0

3 ways it could happen

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<img src="https://tex.z-dn.net/?f=%5Cbf%5Cbegin%7Bmatrix%7D%5Cspace%5Cspace%268%268%5C%5C%20%5Ctimes%262%264%5Cend%7Bmatrix%7D"

Licemer1 [7]

$\huge \color{red}{ ꧁\mathrm{Answer}}꧂$

The answer is 2112

4 0

2 years ago

A college parking lot is 140 ft long and 90 ft wide. The college wants to increase the area of the lot by 29% by adding strips o

Novay_Z [31]

The initial dimenssions of the park lot are:

length: 140 ft
width: 90 ft

initial area: 140 * 90 = 12,600 ft^2

Area increased 29% = 12,600 * 1.29 = 16,254 ft^2

width of the strips: x

New length: 140 + x

New width: 90 + x

New area: (140+x)(90+x) = 16,254

Solution of the equation:

12600 + 230x + x^2 = 16254

=> x^2 + 230x - 3654 = 0

Use the quadratic formula.

x = {-230 +/- √[ 230^2 - 4*1*(-3654) ]} / 2 =

x = 14.92

The other solution is negative so it is discarded.

Answer: 15 ft

5 0

3 years ago

What is 3,567,194 rounded

coldgirl [10]

4,000,000 is 3,567,194 rounded (-:

4 0

3 years ago

Find the vertex and length of the latus rectum for the parabola. y=1/6(x-8)^2+6

Ivan

Step-by-step explanation:

If the parabola has the form

$y = a(x - h)^2 + k$ (vertex form)

then its vertex is located at the point (h, k). Therefore, the vertex of the parabola

$y = \dfrac{1}{6}(x - 8)^2 + 6$

is located at the point (8, 6).

To find the length of the parabola's latus rectum, we need to find its focal length <em>f</em>. Luckily, since our equation is in vertex form, we can easily find from the focus (or focal point) coordinate, which is

$\text{focus} = (h, k +\frac{1}{4a})$

where $\frac{1}{4a}$ is called the focal length or distance of the focus from the vertex. So from our equation, we can see that the focal length <em>f</em> is

$f = \dfrac{1}{4(\frac{1}{6})} = \dfrac{3}{2}$

By definition, the length of the latus rectum is four times the focal length so therefore, its value is

$\text{latus rectum} = 4\left(\dfrac{3}{2}\right) = 6$

5 0

3 years ago

A wire 30 feet long is stretched from the top of a flagpole to the ground at a point 15 feet from the base of the pole. How high

sweet-ann [11.9K]

Answer:

28.3

Step-by-step explanation:

Use the Pythagorean Theorem to solve for the answer. 10^2 + x^2 = 30^2

7 0

3 years ago

Read 2 more answers