Answer:
Ezra can water at most approximately 8 sunflower plants with the remaining amount of water.
Step-by-step explanation:
Given the inequality function
0.7S+0.5L≤11 where S represent the number of sunflower plants and L represent the number of lily plants Ezra's water supply can water, if Ezra waters 10 lily plants, then we can calculate the maximum amount of sunflower plant that he can water with the remaining amount of water by simply substituting L = 10 into the inequality function as shown;
0.7S+0.5L≤11
0.7S+0.5(10)≤11
0.7S+5≤11
Taking 5 to the other side:
0.7S≤11-5
0.7S≤6
S≤6/0.7
S≤8.57
This shows that Ezra can water at most approximately 8 sunflower plants with the remaining amount of water.
Answer:
3/10
Step-by-step explanation:
Multiples of 3: 3,6,9,12,15,18
There are 6 in the numbers 1-20
P(multiple of 3) = number of "multiples of 3" / total
= 6/20
=3/10
Answer:
A)14 Units is the answer for this question
but check it
Answer:
Yes.
Step-by-step explanation:
If a graph G doesn't have a circuit, we must have that

where
is the number of edges of the graph and
the number of vertices. However, in this case it holds that

Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The probability of passing the test is 
The sample size is n = 10
Generally the distribution of the comprehensive testing of equipment follows a binomial distribution
i.e

and the probability distribution function for binomial distribution is

Here C stands for combination hence we are going to be making use of the combination function in our calculators
Generally the probability that at least 9 pass the test is mathematically represented as

=> ![P(X \ge 9) = [^{10}C_9 * (0.95)^9 * (1- 0.95)^{10-9}] + [^{10}C_{10} * (0.95)^{10} * (1- 0.95)^{10-10}]](https://tex.z-dn.net/?f=P%28X%20%5Cge%209%29%20%3D%20%20%5B%5E%7B10%7DC_9%20%2A%20%20%280.95%29%5E9%20%2A%20%20%281-%200.95%29%5E%7B10-9%7D%5D%20%2B%20%5B%5E%7B10%7DC_%7B10%7D%20%2A%20%20%280.95%29%5E%7B10%7D%20%2A%20%20%281-%200.95%29%5E%7B10-10%7D%5D)
=> ![P(X \ge 9) = [0.3151] + [0.5987]](https://tex.z-dn.net/?f=P%28X%20%5Cge%209%29%20%3D%20%20%5B0.3151%5D%20%2B%20%5B0.5987%5D%20)
=> 