All categories

3 years ago

Find the slope of (7, 9) and (2, 12)

Mathematics

2 answers:

slega [8]3 years ago

6 0

The slope of the line that goes through two points $(x_1, y_1)$ and $(x_2, y_2)$ is:

$\dfrac{y_1-y_2}{x_1-x_2}$

The two points we are given is (7,9) and (2,12). Substitute these values into the formula for the slope

$=\dfrac{12-9}{2-7}$

Simplify

$=\dfrac{3}{-5}$

Simplify again

$=-\dfrac{3}{5}$

This should be your answer. Let me know if you need any clarifications, thanks!

~ Padoru

Roman55 [17]3 years ago

3 0

Answer:

-3/5

Step-by-step explanation:

You might be interested in

Solve for x……………………….

Jobisdone [24]

Answer:

Step-by-step explanation:

Find other side:

116 + x = 180

-116 -116

------------------

x = 64

Find missing triangle angle:

50 + 64 + x = 180

114 + x = 180

-114 -114

-------------------

x = 66

Hope this helped.

4 0

3 years ago

Read 2 more answers

A machine in a factor makes 2o gidgets every 1/4 hour. How many gidgets are made every hour ?

Dahasolnce [82]

Answer:

lol

Step-by-step explanation:

lollololol

llllllllllllllllllllllllooooooooooooooooooooooooooooooooooooooooollllllllllllllllllllll

6 0

3 years ago

Help me please please help

Dmitrij [34]

1) 8y + 9 2) 2n + 4 3) 3d + 5h

rearrange the equations and combine like terms. combine the terms with the same variables and add / subtract them.

for example number 1:

9y - 11 + 20 - y

is the same thing as

9y - y + 20 - 11

and now you can easily combine them:

8y + 9

i hope this helps!

4 0

3 years ago

A) 7.7 ft b) 13.4 ft c) 10.3 ft d) 12.3 ft

ELEN [110]

Answer:

D. 12.3 ft

Step-by-step explanation:

This problem requires the use of trigonometric ratios. This one specifically uses the cosine ratio as it provides the hypotenuse and is asking for the side that is adjacent to the angle.

cos(40°)=a/16

cos(40°)×16=a/16×16

cos(40°)×16=a

a=12.256 ft

The length of side a is D. 12.3 ft.

3 0

3 years ago

Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal

lisabon 2012 [21]

Given the following functions below,

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}\text{ and} \\ g(x)=\frac{4x^2-16x+16}{4x+48} \end{gathered}$

Factorising the denominators of both functions,

Factorising the denominator of f(x),

$\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}$

Factorising the denominator of g(x),

$\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}$

Multiplying both functions,

$undefined$

4 0

1 year ago