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2 years ago

Help me please!!!!!!!!!!!!!!!????

Mathematics

2 answers:

VashaNatasha [74]2 years ago

7 0

Answer:

I think it's A, as I have not done transformations yet but hope it helps

kari74 [83]2 years ago

6 0

The second choice because m is connected to n so the correlation between all of them is 4 and so m moved 4 up

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How o I get the awnser to 9s+3=57 I need help asap im in 8th grade

PIT_PIT [208]

First subtract 3 from both sides of the equal sign.
9s + 3 = 57
- 3 -3
9s = 54

Then divide both sides by 9.
9s = 54
/9 /9
s = 6

You can check it by plugging it back into the equation.
9s + 3 = 57
9 * 6 + 3= 57
54 + 3 = 37
57 = 57
Yep! It's correct! :)

Hope that helped. Algebra can be tricky sometimes I know but it's really just balancing equations.

3 0

4 years ago

If you have ordered pairs (4, 6) and (2, 3). WHAT IS THE SLOPE OF THE LINE?

tangare [24]

Answer:

3/2

Step-by-step explanation:

Okay, I can represent this equation as rise over run

the coordinates 4,6 are subcoordinates 1

y: 6 - 3 = 3

x: 4 - 2 = 2

Since it is RISE over run then Y is the numerator and X is the denominator.

So the slope is 3/2.

5 0

3 years ago

Match the numerical expressions to their simplest forms.

Aloiza [94]

Answer:

$(a^6b^1^2)^\frac{1}{3}$ = $a^2b^4$

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$ = $a^3b^2$

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$ = $a^2b$

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$ = $ab^3$

Step-by-step explanation:

Simplify each of the expressions:

$(a^6b^1^2)^\frac{1}{3}$

Distribute the exponent. Multiply the exponent of the term outside of the parenthesis by the exponents of the variable.

$(a^6b^1^2)^\frac{1}{3}$

$a^6^*^\frac{1}{3}b^1^2^*^\frac{1}{3}$

Simplify,

$a^2b^4$

Use a similar technique to solve this problem. Remember, a fractional exponent is the same as a radical, if the denominator is (2), then the operation is taking the square root of the number.

$\frac{(a^5b^3)^\frac{1}{2}}{(ab)^-^\frac{1}{2}}$

Rewrite as square roots:

$\frac{\sqrt{a^5b^3}}{\sqrt{(ab)}^-^1}$

A negative exponent indicates one needs to take the reciprocal of the number. Apply this here:

$\frac{\sqrt{a^5b^3}}{\frac{1}{\sqrt{ab}}}$

Simplify,

$\sqrt{a^5b^3}*\sqrt{ab}$

Since both numbers are under a radical, one can rewrite them such that they are under the same radical,

$\sqrt{a^5b^3*ab}$

Simplify,

$\sqrt{a^6b^4}$

Since this operation is taking the square root, divide the exponents in half to do this operation:

$a^3b^2$

$(\frac{a^5}{a^-^3b^-^4})^\frac{1}{4}$

Simplify, to simplify the expression in the numerator and the denominator, the base must be the same. Remember, the base is the number that is being raised to the exponent. One subtracts the exponent of the number in the denominator from the exponent of the like base in the numerator. This only works if all terms in both the numerator and the denominator have the operation of multiplication between them:

$(\frac{a^8}{b^-^4})^\frac{1}{4}$

Bring the negative exponent to the numerator. Change the sign of the exponent and rewrite it in the numerator,

$(a^8b^4)^\frac{1}{4}$

This expression to the power of the one forth. This is the same as taking the quartic root of the expression. Rewrite the expression with such,

$\sqrt[4]{a^8b^4}$

SImplify, divide the exponents by (4) to simulate taking the quartic root,

$a^2b$

$(\frac{a^3}{ab^-^6})^\frac{1}{2}$

Using all of the rules mentioned above, simplify the fraction. The only operation happening between the numbers in both the numerator and the denominator is multiplication. Therefore, one can subtract the exponents of the terms with the like base. The term in the denomaintor can be rewritten in the numerator with its exponent times negative (1).

$(a^3^-^1b^(^-^6^*^(^-^1^)^))^\frac{1}{2}$

$(a^2b^6)^\frac{1}{2}$

Rewrite to the half-power as a square root,

$\sqrt{a^2b^6}$

Simplify, divide all of the exponents by (2),

$ab^3$

7 0

3 years ago

A blue boat and a red boat are on the same side of a lake and are 18 miles apart. The blue boat is 30 miles from a lighthouse on

rewona [7]

9514 1404 393

Answer:

red boat distance: 42 miles
angle at lighthouse: 22°

Step-by-step explanation:

The Law of Cosines can be used to find the distance from the red boat to the lighthouse.

b² = l² +r² -2lr·cos(B)

b² = 18² +30² +2·18·30·cos(120°) = 1764

b = √1764 = 42

The distance from the red boat to the lighthouse is 42 miles.

The angle at the lighthouse can be found using the law of sines.

sin(L)/l = sin(B)/b

L = arcsin(l/b·sin(B)) = arcsin(18/42·sin(120°)) ≈ 21.79°

The angle between the boats measured at the lighthouse is about 22°.

8 0

3 years ago

What is 5,384,981 to the nearest ten-thousands place?

Harlamova29_29 [7]

Answer:

5,380,000

Step-by-step explanation:

8 0

3 years ago