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LUCKY_DIMON [66]
2 years ago
10

Draw a number line to represent the street sign below

Mathematics
1 answer:
galina1969 [7]2 years ago
6 0
Its kind of like how it is on a car to tell how fast your going i hoped this helped!

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3x-3=2x<br><br> Please help me...?<br> 10 points given
svetoff [14.1K]
3x - 3 = 2x

Add 3 on both sides

3x - 3 + 3 = 2x + 3
3x = 2x + 3

Subtract 2x on both sides

3x - 2x = 2x + 3 - 2x
3x - 2x = 3
x = 3

So, your final answer is x = 3.
6 0
3 years ago
Read 2 more answers
determine the equation of the circle if its center is (8,-6) and which passes through the points (5,-2).
ser-zykov [4K]

Answer:

(x - 8)² + (y + 6)² = 25

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k ) are the coordinates of the centre and r is the radius

Here (h, k ) = (8, - 6 ) , then

(x - 8)² + (y - (- 6))² = r² , that is

(x - 8)² + (y + 6)² = r²

The radius is the distance from the centre to a point on the circle

Calculate r using the distance formula

r = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (8, - 6 ) and (x₂, y₂ ) = (5, - 2 )

r = \sqrt{(5-8)^2+(-2-(-6))^2}

  = \sqrt{(-3)^2+(-2+6)^2}

  = \sqrt{9+4^2}

  = \sqrt{9+16}

   = \sqrt{25}

   = 5

Then equation of circle is

(x - 8)² + (y + 6)² = 5² , that is

(x - 8)² + (y + 6)² = 25

6 0
2 years ago
If x and y vary inversely and x = 5 when y = -3.5, what is the value of x when y = 10?
Solnce55 [7]

Answer:

Step-by-step explanation:

k = xy

Putting values of x and y in the equation

k = (5)(-3.5)

= - 17.5

Finding value of x when y = 10

k = xy

- 17.5 = x10

Bringing like terms on one side

- 17.5 - 10 = x

-27.5 = x

5 0
3 years ago
10 - d = -34 - 5d show the work
Naddika [18.5K]

Answer:

d = 11

Step-by-step explanation:

10 - d = -34 - 5d

10 (- d + d) = -34 (- 5d + d)

10 = -34 - 4d

10 + 34 = (-34 + 34) - 4d

44 = 4d

44/4 = 4d/4

d = 11

3 0
3 years ago
Please anyone answer me
ollegr [7]

Let's divide the shaded region into two areas:

area 1: x = 0 ---> x = 2

ares 2: x = 2 ---> x = 4

In area 1, we need to find the area under g(x) = x and in area 2, we need to find the area between g(x) = x and f(x) = (x - 2)^2. Now let's set up the integrals needed to find the areas.

Area 1:

A\frac{}{1}  = ∫g(x)dx =  ∫xdx =  \frac{1}{2}  {x}^{2}  | \frac{2}{0}  = 2

Area 2:

A\frac{}{2}  = ∫(g(x) - f(x))dx

= ∫(x -  {(x - 2)}^{2} )dx

=  ∫( - {x}^{2}  + 5x - 4)dx

= ( - \frac{1}{3}{x}^{3} +   \frac{5}{2} {x}^{2}  - 4x)   | \frac{4}{2}

= 2.67 - ( - 0.67) = 3.34

Therefore, the area of the shaded portion of the graph is

A = A1 + A2 = 5.34

3 0
3 years ago
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