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SpyIntel [72]
1 year ago
10

Write 9/20 as a decimal number

Mathematics
2 answers:
sattari [20]1 year ago
5 0

Answer: 0.45

........................

Vesnalui [34]1 year ago
4 0
0.45

Why?
Because it’s 9/20 as a decimal number

Hope this helped!!!
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Which number would be classified as an integer on the Venn diagram?
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Integers involve with negative, so D isn't the correct answer the correct answer will be A.

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What is the cube root of -729a^9 b^6?
Morgarella [4.7K]

Answer:

-9a^3b^2

Step-by-step explanation:

Your Welcome!

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DochEvi [55]

Answer:

25.12 in^3.

Step-by-step explanation:

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3 0
2 years ago
Read 2 more answers
Find the first, fourth, and eighth terms of the sequence. A(n) = –3 • 2^n–1
Sphinxa [80]
A(n) = –3 • 2⁽ⁿ⁻¹⁾

for n = 1 ,  A₁ = -3.(2)⁰ = -3
for n = 2 ,  A₂ = -3.(2)¹ = -6
for n = 3 ,  A₃ = -3.(2)² = -12
for n = 4 ,  A₄ = -3.(2)³ = -24
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for n = 8 ,  A₈ = -3.(2)⁷ = -384


4 0
2 years ago
Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th
Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

  • Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
  • Symmetry: For all x,y, if xRy then yRx.
  • Transitivity: For all x,y,z, If xRy and yRz then xRz.

Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

5 0
3 years ago
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