The answer is 20 ashsnenzhwnebdhdjsjdn
Answer:
f^(-1)(x) = -3x/(3x-3)
Step-by-step explanation:
1) replace f(x) by y
● y = 3x/(5x+3)
2) exchange x and y
● y = 3x/(5x+3)
● x = 3y / (3y +3)
3) solve for y
● x = 3y / (3y +3)
● x (3y +3) = 3y
● 3xy + 3x = 3y
● 3xy - 3y = -3x
● y (3x - 3) = -3x
● y = -3x /(3x-3)
4) replace y with f^(-1)(x)
● y = -3x/(3x-3)
● f^(-1)(x) = -3x/(3x-3)
The straight line distance from the starting point is 41 miles.
<u>Explanation:</u>
Given:
Distance covered towards north, n = 9 miles
Distance covered towards east, e = 40 miles
Distance from the origin to the end, x = ?
If we imagine this, then the route forms a right angle triangle
where,
n is the height
e is the base
x is the hypotenuse
Using pythagoras theorm:
(x)² = (n)² + (e)²
(x)² = (9)² + (40)²
(x)² = 1681
x = 41 miles
Therefore, the straight line distance from the starting point is 41 miles.
F(X)= x+1/4x-2
f(2) = (2 + 1)/[(4)(2) - 2]
f(2) = 3/6 = 1/2
<h3>
Answer:</h3>
<u>By angle bisector property</u>,
- 11x + 23 = 8x + 35
- 11x - 8x = 35 - 23
- 3x = 12
- x = 4°
So, <u>m∠ABD</u> = 8x + 35
<u>m∠CBD</u> = 11x + 23
<u>m∠ABC</u> = 67° + 67° = 134°