Question

Don’t even know how i got this far in geometry lol

Answer 1

$\qquad\qquad\huge\underline{{\sf Answer}}☂$

Let's find the Area of sector ~

$\qquad \sf \dashrightarrow \: \dfrac{ \theta}{360} \times \pi{r}^{2}$

$\qquad \sf \dashrightarrow \: \dfrac{ 270}{360} \times \pi{6}^{2}$

$\qquad \sf \dashrightarrow \: \dfrac{ 3}{4} \times {36}^{} \pi$

$\qquad \sf \dashrightarrow \:3 \times 9 \pi$

$\qquad \sf \dashrightarrow \:27\pi \: \: ft {}^{2}$