since the polygon has 8 chambers the angle of one chamber = 360/8 = 45°
so the angle WOP = 45°
now drawing a imaginary line which seperates the triangleWOP into half
so the angle of imaginary line is 45/2 = 22.5
sin(theta) = opp/hyp
since WP (opp) is unknown. take as x
sin(22.5) = x/44
0.383×4 = x
x = 1.532 (app) = 1.5 cm
perimeter = 1.5 × 8
= 12 cm
area of triangle WOP = 2×1/2 ×bh = bh
= 4×1.5
= 6 cm²
so the area of regular polygon = 8× area of a triangle
= 48 cm²
Answer:
44 in²
Step-by-step explanation:
The figure is composed of a triangle, a rectangle and a trapezium.
Area of the triangle = 
bh = × 3 × 4 = 6 in²
Area of the rectangle = lb = 10 × 3 = 30 in²
Area of trapezium = h (a + b)
where h is the height and a, b the parallel bases, thus
area of trapezium = × 2 × (5 + 3) = 1 × 8 = 8 in²
Total area = 6 in² + 30 in² + 8 in² = 44 in²
The answer is 1.
3^3 = 27
27^-1 = 1/27
1/27 x 27 = 1
I took this test and got this question right.
Answer:
Supplementary and Complementary
