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Hitman42 [59]
2 years ago
9

Find the value of X round your answer to the nearest tenths

Mathematics
1 answer:
vlabodo [156]2 years ago
6 0

Answer:

x = 17.9

Step-by-step explanation:

tan40^{0} =\frac{15}{x}

x=\frac{15}{tan40^{0} } =17.88

rounded: 17.9

Hope this helps

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John spent half of his weekly allowance
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$6

Step-by-step explanation:

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3. Leeland can eat 1 hotdog in 20 minutes. What is his unit rate in hotdogs
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Look at the attachment pls!!
Naddika [18.5K]

The terms -12x^2y and 4x^2y can be added to 3x^2y to result in a monomial.

Step-by-step explanation:

Given term is;

3x^2y

A monomial is an algebraic expression that consists of only one term.

So in the given expressions, we will add the terms which have same variables as given terms.

Given options are;

3xy\\-12x^2y\\2x^2y^2\\7xy^2\\-10x^2\\4x^2y\\3x^3

The terms -12x^2y and 4x^2y can be added to 3x^2y to result in a monomial.

4 0
3 years ago
Solve the system of equations.
Xelga [282]

Answer:

  b.  x=1, y=2, z=3

Step-by-step explanation:

The system of equations ...

  • 3x +2y +z = 10
  • 9x -6y +z = 0
  • x -y -3z = -10

has solution (x, y, z) = (1, 2, 3) . . . . matches choice B.

_____

While it is convenient to solve this using a graphing calculator or web site, one can easily solve the system by hand.

Subtract the second equation from 3 times the first:

  3(3x +2y +z) -(9x -6y +z) = 3(10) -(0)

  12y + 2z = 30 . . . . simplify

Dividing this result by 2 gives ...

  6y +z = 15 . . . . . . [eq4]

Subtract 3 times the third equation from the first:

  (3x +2y +z) -3(x -y -3z) = (10) -3(-10)

  5y +10z = 40 . . . . simplify

  y + 2z = 8 . . . . . . . divide by 5 . . . . . [eq5]

The two equations [eq4] and [eq5] can be solved any of the ways you usually solve two equations in two variables. Here, we'll use the first equation to write an expression for z that we can substitute into the second equation.

  z = 15 -6y . . . . . subtract 6y from [eq4]

  y + 2(15 -6y) = 8 . . . . . substitute for z in [eq5]

  -11y +30 = 8 . . . . . simplify

  -11y = -22 . . . . . . . subtract 30

  y = 2 . . . . . . . . . . . divide by the coefficient of y

  z = 15 -6(2) = 3 . . . . substitute for y in our equation for z

Substituting these values for y and z into the third original equation gives ...

  x - 2 -3(3) = -10

  x -11 = -10 . . . . . . . . simplify

  x = 1 . . . . . . . . . . . . add 11

The solution to the above system of equations is (x, y, z) = (1, 2, 3).

_____

<em>Comment on the problem statement</em>

Math is generally unforgiving of imprecision. The given system of equations has no variable "z", and some other typos are apparently involved. That is why we rewrote the system to the equations shown above.

It is very easy to mistake z for 2, or g for 9, or o for 0, or 1 for 7. There are other confusions that are possible, as well. Letters I (eye) and l (ell) are easily confused, and may be confused with 1 (one) as well. Sometimes y and 4, or 4 and 9, can also be written so as to be difficult to tell apart. Great care must be taken when handwriting these symbols.

7 0
3 years ago
Use the Euclidean Algorithm to compute the greatest common divisors indicated. (a) gcd(20, 12) (b) gcd(100, 36) (c) gcd(207, 496
coldgirl [10]

Answer:

(a) gcd(20, 12)=4

(b) gcd(100, 36)=4

(c) gcd(496,207 )=1

Step-by-step explanation:

The Euclidean algorithm is an efficient method for computing the greatest common divisor of two integers, without explicitly factoring the two integers.

The Euclidean algorithm solves the problem:

<em>                                   Given integers </em>a, b<em>, find </em>d=gcd(a,b)<em />

Here is an outline of the steps:

  1. Let a=x, b=y.
  2. Given x, y, use the division algorithm to write x=yq+r.
  3. If r=0, stop and output y; this is the gcd of a, b.
  4. If r\neq 0, replace (x,y) by (y,r). Go to step 2.

The division algorithm is an algorithm in which given 2 integers N and D, it computes their quotient Q and remainder R.

Let's say we have to divide N (dividend) by D (divisor). We will take the following steps:

Step 1: Subtract D from N repeatedly.

Step 2: The resulting number is known as the remainder R, and the number of times that D is subtracted is called the quotient Q.

(a) To find gcd(20, 12) we apply the Euclidean algorithm:

20 = 12\cdot 1 + 8\\ 12 = 8\cdot 1 + 4\\ 8 = 4\cdot 2 + 0

The process stops since we reached 0, and we obtain gcd(20, 12)=4.

(b) To find gcd(100, 36) we apply the Euclidean algorithm:

100 = 36\cdot 2 + 28\\ 36 = 28\cdot1 + 8\\ 28 = 8\cdot 3 + 4\\ 8 = 4\cdot 2 + 0

The process stops since we reached 0, and we obtain gcd(100, 36)=4.

(c) To find gcd(496,207 ) we apply the Euclidean algorithm:

496 = 207\cdot 2 + 82\\ 207 = 82\cdot 2 + 43\\ 82 = 43\cdot 1 + 39\\ 43 = 39\cdot 1 + 4\\ 39 = 4\cdot 9 + 3\\ 4 = 3\cdot 1 + 1\\ 3 = 1\cdot 3 + 0

The process stops since we reached 0, and we obtain gcd(496,207 )=1.

3 0
3 years ago
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