I need a answer for number 7

Nina [5.8K]

30)

$\bf \begin{array}{llll}
y=&{{ a}}x^2&{{ +b}}x&{{ +c}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}
\\\\\\
discriminant\implies b^2-4ac=
\begin{cases}
0&\textit{one solution}\\
positive&\textit{two solutions}\\
negative&\textit{no solution}
\end{cases}$

31)

a simple case for that would just be, using an equation with an imaginary value, let's do so

$\bf \sqrt{-5}=x\implies \sqrt{-1\cdot 5}=x\implies \sqrt{-1}\sqrt{5}=x\implies i\sqrt{5}=x\\\\
-------------------------------\\\\
\textit{so, we'll use that imaginary value then}\\\\
\sqrt{-5}=x\implies -5=x^2\implies 0=x^2+5\implies \boxed{y=x^2+5}$

when you get a "solution" or zero with an "i" or an imaginary value, is just a way to say, there's really no solution, the function never touches the x-axis

3 0

4 years ago

Gerry ran 3/8 of a mile on Monday. He ran 5/8 of a mile on tuesday he ran 1/2 mile on Wednesday how many miles in all did Gerry

pickupchik [31]

1 and 1/2 miles in total

3 0

3 years ago

Read 2 more answers

45 × ÷ 15 = 45 please answere me

Bingel [31]

Answer:

15

Step-by-step explanation:

multiply both sides by 15

45x=675

Divide both sides by 45

x=15

5 0

3 years ago

A box of nails weighs 130 pounds when it is 2/3 full. It weighs 74 pounds when it is 3/8 full. What is the weight of the box?

NeTakaya

Let the weight of the full Volume of nails in the box be W.
Let the weight of the box be B.

2/3 W + B = 130 ........i From the first statement.
3/8 W + B = 74 ......ii    From the second statement.

Equation (i) Minus (ii)

2/3 W - 3/8 W + B - B = 130 - 74
(16W - 9W) / 24    = 56

7W / 24 = 56.
W = 56 * 24 / 7
W      = 192 Pounds.

Substituting V = 64 in equation (i)
2/3 W + B = 130
2/3 * 192 + B = 130
2 * 64 + B = 130
128 + B = 130
B = 130 -128 = 2.

Therefore, weight of box, B = 2 pounds.

7 0

4 years ago

We say that an integer a is a type 0 integer if there exists an integer n such that a = 3n. An integer a is a type 1 integer if

Delicious77 [7]

Answer:

Proof below

Step-by-step explanation:

Let's assume a is a type 1 integer. By definition, it means we can find an integer n such that

a=3n+1

We need to prove $a^2$ is a type 1 integer